The volume of the sphere is: V=4πr3/3.
Then r=0,62 x (cubic root from V)
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Call the volume 'V'.
Call the radius 'R'.
The volume of a sphere is V = 4/3 (pi) R3 .
Multiply both sides of the formula by 3/4 :
3/4 V = (pi) R3
Divide each side by pi :
3V/4 pi = R3
Take the cube root of each side :
R = cube root of (3V/4 pi)
The first answer up above simplified this somewhat, by taking (3/4 pi)
out of the cube root, and you wind up with:
R = 0.62 times the cube root of ( V ) . (rounded)
You need to know if the sphere is solid or hollow. You also need the "density" in terms of pounds weight per unit volume. Then Volume = Mass/Density And Radius = cuberoot[3*Vol/(4*pi)]
Fist you've got to find the volume of the sphere, if the radius was 4cm then it would be...4/3*pi*r3=268cm V of cylinder= pi*r2*l (the radius for example is 8cm) 268=pi*64*l L=268/64pi =1.3cm
True. The radius is half the diameter.
If by circle you mean sphere, then the volume of a sphere is: 4/3 * pi * radius^3. If you already know the volume, then here's what you do: 1. Multiply the volume by 3/4. 2. Divide the volume by pi. 3. Take the cube root of both sides In other words, the formula for radius when volume is known is: ( ( Volume * 3 ) / ( 4 * pi ) ) ^ (1/3)
To determine empty space, we will assume that the sphere fits snugly(so that each side of the cube is touching the sphere). First, we take the volume of the cube, which is just one of its side lengths cubed(side length X side length X side length). Record this quantity. Then we find the volume of the sphere. The formula for the volume of a shere is (4/3) Pi r cubed. Since the sphere fits snugly, we know that the radius is half of the side length. We then take the cube volume and subtract the sphere volume, and that is the empty space remaining.
You need to know if the sphere is solid or hollow. You also need the "density" in terms of pounds weight per unit volume. Then Volume = Mass/Density And Radius = cuberoot[3*Vol/(4*pi)]
You need to know it's density to find the volume, then 4/3 pi r^3 to get radius, then double radius is diameter.
If you know the radius, use the formula: volume = (4/3) x pi x radius3.If you know the radius, use the formula: volume = (4/3) x pi x radius3.If you know the radius, use the formula: volume = (4/3) x pi x radius3.If you know the radius, use the formula: volume = (4/3) x pi x radius3.
True. The radius is half the diameter.
Fist you've got to find the volume of the sphere, if the radius was 4cm then it would be...4/3*pi*r3=268cm V of cylinder= pi*r2*l (the radius for example is 8cm) 268=pi*64*l L=268/64pi =1.3cm
Measuring the volume of a baseball is a tough chemistry equation. To do so, you would have to measure the circumference to find the radius. Next, you would find the volume of a sphere. You would also have to know the density of water to complete the equation.
If by circle you mean sphere, then the volume of a sphere is: 4/3 * pi * radius^3. If you already know the volume, then here's what you do: 1. Multiply the volume by 3/4. 2. Divide the volume by pi. 3. Take the cube root of both sides In other words, the formula for radius when volume is known is: ( ( Volume * 3 ) / ( 4 * pi ) ) ^ (1/3)
Start by finding the volume of the sphere. You know it's radius is 6cm. The volume of the sphere with respect to the radius is: v = 4/3πr3 So you can plug that radius in to get the volume: v = 4/3π(6cm)3 v = 4/3π216cm3 v = 288πcm3 We know that the volumes of the sphere and the cone are equal, and that the base radius of the cone is six centimeters. Using those, we can work out the cone's height. The volume of a cone is calculated as: v = πr2h we already have the volume and radius, so we simply have to rearrange that equation and solve for h v = πr2h h = v / πr2 and simply plug in our values: h = (288π cm3) / π(6cm)2 h = 288cm3 / 36cm2 h = 8cm So the height of the cone is eight centimeters
To work out the area of a sphere, you have to know its radius. Once you know that: -- 'square' the radius (multiply radius times radius) -- multiply that result by 12.5664 The result is near the area of the sphere.
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The change in solution volume will be the volume of the sphere. Let's call that V We know that the volume of a sphere is 4/3 Pi x r^3 So the cube root of 3v/4Pi is the radius, double it and you have the diameter. OR Volume of sphere is 1/6 Pixd^3 so 6V/Pi is the diameter cubed. Take the cube root of 6V/Pi and that is the diameter.
Volume of a sphere = 4/3 x pi x r3= 3,054 m3Since we only know the radius to one figure of precision then the correct answer for the volume should also only have one figure of precision 3 000 m3.The answer can not have more precision than the starting values. In other words the answer can not give more information than what it was provided with.