figure what x is times by 2 do the same with 9 ex v=2 v4-v5=8-5=3
x2-9x = x(x-9)
Divide both sides of the equation by x: x2 = 9x x2 / x = 9x / x x = 9
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
x2+9x-36 = (x-3)(x+12) when factored
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
x2+9x+18 find factors of 18 that add up to 9, in this case 6&3 (x+6)(x+3)
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
x2-9x+18 = (x-3)(x-6) when factorised
Assuming you mean: (9x × x2)2 Then we can say: = (9x3)2 = 81x6
No.
A binomial
x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)