that is your problem
This is a simple math permutation. the answer is 6 factorial which means 6 * 5 * 4 * 3 * 2 * 1 (aka 720)
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
3 items (or people) can line up in 6 different sequences. 6 items (or people) can line up in 720 different sequences.
6. Because you first have to arrange in order then find the number in the middle: 1 3 4 [6] 6 6 9
3! = 1 x 2 x 3 = 6 ways.
This is a Permutation problem; nPr is the formula which assumes order matters. You have n=6 & r=3. Formula is: 6! / (6-3)! or 6!/3! = 120.
In a line in 6! = 6*5*4*3*2*1 = 720 ways.
6 -- abc, acb, bac, bca, cab, cba
This is a simple math permutation. the answer is 6 factorial which means 6 * 5 * 4 * 3 * 2 * 1 (aka 720)
well let's see....setetstseeststetesuh.... that would be 6Mathematically, it would be the number of permutations of three things taken three at a time=3!=3*2*1=6.
The answer is 5 factorial or 5*4*3*2*1 or 120
If you have three DIFFERENT letters, you can arrange them in 3! = 1 x 2 x 3 = 6 different ways.
Yes, you can.
2-3=-1- -5= -6 +6=0 , Patrick Star
6! = 6*5*4*3*2*1 = 720
3 items (or people) can line up in 6 different sequences. 6 items (or people) can line up in 720 different sequences.
6. Because you first have to arrange in order then find the number in the middle: 1 3 4 [6] 6 6 9