0
I presume each number can be used once only.
3 + (4 x 5/10) = 3 + 2 = 5
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∙ 11y ago
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How do you get an answer of 11 when using the number 4 only four times?
4/.4 + 4/4 = 10 + 1 = 11.
How do you figure out the different 4 number combinations using the numbers between 0 and 9?
10 raised to power 4
How do you write a number sentence using 3 4 5 6 7 and 10 equals 3 using parenthesis?
(3x4+5+6+7)/10=3
How many 4 number combinations are their using numbers 0 9?
10,000 * * * * * WRONG! That is the number of permutations, NOT the number of combinations. The number of combinations denoted by nCr = n!/[r!*(n-r)!] = 10!/[4!*6!] = 10*9*8*7/(4*3*2*1) = 210
Using any mathematical operations you need to find the answer 254 using 3 4 6 6 8 and 10 without repeating a number?
can do it without using the 3, is that allowed? 4 x 6 x 10 = 240 + 6 + 8 = 254
What is 1 minus one fourth?
1 - 1/4get common denominators4/4 - 1/4subtract the top numbers3/4
How do you get 10 with only using the number 4?
Many ways, but one example is: 4+4+(4/4)+(4/4)= 10.
How do you get 40 using numbers 2 3 4 and 10?
The closest you can get by: Using Each Number Once With Powers: 10 th the second power - 4 th the third power=46 Using each Number Once Without Powers:(4*10)-3+2 Using an indefinite amount of each number:4-*10+(3*2)-(2+2+2)
How do you get an answer of 11 when using the number 4 only four times?
4/.4 + 4/4 = 10 + 1 = 11.
Write a number sentence using the number 3 4 5 6 7 10 only once and plus - x?
3 - 4 + 5 * 6 + 7 > 10
How do you figure out the different 4 number combinations using the numbers between 0 and 9?
10 raised to power 4
How do you write a number sentence using 3 4 5 6 7 and 10 equals 3 using parenthesis?
(3x4+5+6+7)/10=3
How do you make the number 2 using 1 2 4 and 9?
9+1-4(2) 10-8=2
How do you make the number 100 using 1 4 9 2?
(9 + 1)^(4/2) = 10^2 = 100.
How do you make 24 using the number 10 9 6 and 5?
6*(9 + 5 - 10) = 6*(14 - 10) = 6*4 = 24
How many 4 number combinations are their using numbers 0 9?
10,000 * * * * * WRONG! That is the number of permutations, NOT the number of combinations. The number of combinations denoted by nCr = n!/[r!*(n-r)!] = 10!/[4!*6!] = 10*9*8*7/(4*3*2*1) = 210
Using any mathematical operations you need to find the answer 254 using 3 4 6 6 8 and 10 without repeating a number?
can do it without using the 3, is that allowed? 4 x 6 x 10 = 240 + 6 + 8 = 254
