In short, you don't.
The strdate() function returns a formatted string that represents the current date. It is not intended that this result be used in a date calculation such as increment. The complexities of converting back to month day and year, and then dealing with the special rules of the Gregorian calender, along with leap years is unrealistic, given that there are library functions that will do this for you already. Try this...
#include <time.h>
#include <iostream>
using namespace std;
...
char cdate[9];
time_t tt = time(NULL) + 86400; // tomorrow
struct tm *tomorrow;
tomorrow = localtime (&tt);
strftime(cdate, 9, "%m/%d/%y", tomorrow);
cout << cdate << endl;
In short, you don't.
The strdate() function returns a formatted string that represents the current date. It is not intended that this result be used in a date calculation such as increment. The complexities of converting back to month day and year, and then dealing with the special rules of the Gregorian calender, along with leap years is unrealistic, given that there are library functions that will do this for you already. Try this...
#include <time.h>
#include <iostream>
using namespace std;
...
char cdate[9];
time_t tt = time(NULL);
struct tm *nextyear;
nextyear = localtime (&tt);
nextyear->tm_year ++; // increment year
if (nextyear->tm_mon 29) { // handle feb 29th
nextyear->tm_mon ++;
nextyear->tm_mday = 1;
}
strftime(cdate, 9, "%m/%d/%y", nextyear);
cout << cdate << endl;
The '+=' operator behaves like a pre increment operator.
++a (plus plus a) is pre-incrementing operator to aa=10;printf("%d",++a); /* it will print 11 as ++a increment first a by 1 then prints it */printf("%d",a++); /*it will printf 10 as it is post _ increment operator , it prints the value a first then increment it by 1 */
I assume by 2 plus you really mean ++. This is the increment operator which is used to increment the operand. If placed before the operand, the operator evaluates the incremented operand (prefix increment). If placed after the operand, the operator evaluates the non-incremented operand (postfix increment). +++ and ++++ are meaningless but are assumed to mean incrementing an increment. If you wish to increment an increment, you must use the compound expression ++(++) or (++)++. Thus for the variable x, prefix incrementing twice would be achieved with ++(++x), while postfix incrementing twice would be achieved with (x++)++. You can also mix the two, such as ++(x++) or (++x)++, both of which would increment x twice but would evaluate the increment of x. If postfix increment is not a requirement, it would be much easier to use the compound expression x+=n, where n is the amount you wish to increment. This is the same as saying x=x+n.
If these expressions are stand-alone (not nested), then they do the same thing, ie increment 'n'.
Yes, they are exactly the same, both of them increment k in 1.
The pre and post increment (and decrement) operator is the same in C++ as it is in C.
The '+=' operator behaves like a pre increment operator.
++a (plus plus a) is pre-incrementing operator to aa=10;printf("%d",++a); /* it will print 11 as ++a increment first a by 1 then prints it */printf("%d",a++); /*it will printf 10 as it is post _ increment operator , it prints the value a first then increment it by 1 */
I assume by 2 plus you really mean ++. This is the increment operator which is used to increment the operand. If placed before the operand, the operator evaluates the incremented operand (prefix increment). If placed after the operand, the operator evaluates the non-incremented operand (postfix increment). +++ and ++++ are meaningless but are assumed to mean incrementing an increment. If you wish to increment an increment, you must use the compound expression ++(++) or (++)++. Thus for the variable x, prefix incrementing twice would be achieved with ++(++x), while postfix incrementing twice would be achieved with (x++)++. You can also mix the two, such as ++(x++) or (++x)++, both of which would increment x twice but would evaluate the increment of x. If postfix increment is not a requirement, it would be much easier to use the compound expression x+=n, where n is the amount you wish to increment. This is the same as saying x=x+n.
In C, the ++ operator means to increment the object associated with it. If you said xyz++; for instance, you would increment xyz. (There are pre-increment and post-increment forms, but that is out of scope for this question.) When the C language was enhanced, the new language was called C++, implying that C++ was the "next", or "incremented", version of C.
This is used in languages such as C, C++ and Java. The difference is when the statement is executed. If placed before the variable, the increment is done before other operations, otherwise, after them. This is best shown in an example.a + b++ means to add first, then to increment the variable b.a + ++b means to increment b first, then to do the addition.Similarly, in a = b++, b is copied to a, and then increment; while in a = ++b, variable b is incremented before being copied.
you++ will return the current value of you and increment it. ++you will increment it and then return the new value of you. So, for example: int you = 0; cout << you++; // this will print 0 cout << you; // this will print 1 int you = 0; cout << ++you; // this will print 1 cout << you; // this will also print 1
Efficiency is the same; the difference is when the "++" is evaluated, before or after other operations. For example: a = b++ // This will first copy b to a, then increment b. a = ++b // This will first increment b, then copy it to a. If you have the "++" operator by itself, it makes no different if you use prefix or postfix. a++ is the same as ++a.
If these expressions are stand-alone (not nested), then they do the same thing, ie increment 'n'.
Yes, they are exactly the same, both of them increment k in 1.
For both cases, the ++ operator increments the integer by one. The difference lies in when it makes that increment. Take the following for example: int B = 3 A = ++B // A = 4, B = 4 --------------- int B = 3 A = B++ //A = 3, B = 4 In the prefix example, the increment occurs before the assignment. In the suffix example, the increment occurs after the assignment.
In C and in C++, the ++ operator means to increment. C++ was intended to be the next version, i.e. the incremental next step, of C, hence the use of the ++ operator.