[(1 + 3) x 4] + 2 = [4 x 4] + 2 = 16 + 2 = 18
[[(9*2)/6]!-2]! 1) 9*2 = 18 2) 18/6 = 3 3) 3! = 6 4) 6-2 = 4 5) 4! = 24
4: 2*2 18: 3*3*2 lcm=3*3*2*2= 36
2 and 4/18 + 4 and 3/18 = 6 and 7/18
3/4 Solutions: 1. 18/24 * 6/6 = 3/4 2. 18/24 = factors of 18=2*3*3 and factors of 24=2*2*2*3, then remove the common factors (2*3) and you are left with 3/(2*2)=3/4 =========== Previously answer: 3/4.
The greatest common factor (GCF) of 18 and 4 is 2. 18 = 2 x 3 x 3 4 = 2 x 2 There is no number larger than 2 which can evenly divide both 18 and 4.
Six 4.1/2 = 9/2 = 18/4 18/4 divided by 3/4 is the same as 18/4 x 4/3 then (18 x 4) / (4 x 3) is 72/12 = 6 or remove both 4 from 18/4 divided by 3/4 leaving 18 divided by 3 = 6 or 3/4 x 2 = 1.1/2 and then 1.1/2 x 3 = 4.1/2 so 2 x 3 = 6 or 3/4 = 0.75 4.1/2 = 4.50 if something cost $0.75 how many could be bought with $4.50 is the answer six.
1, 2, 4 1, 3, 9 1, 2, 3, 6, 9, 18
(18/3) + 6 -(2 x 4) = 4
make lower number the same 4/9 x 2/2 = 8/18 3/6 x 3/3 = 9/18 so no 4 ninth is 1 eighteenth less than 3 sixth
3 fractions equivalent to 4 1/2 = 9/2, 18/4, 27/6 4 1/2 = 9/2 9/2 * 2/2 = 18/4 9/2 * 3/3 = 27/6
The factors of 4 are 1, 2, and 4The factors of 18 are 1, 2, 3, 6, 9, and 18 1, 2, 41, 2, 3, 6, 9, 18