You would need to add water. The amount required is entirely dependent on how much volume you currently have. If the current volume is x then the question can be rewritten as:
10%x/(x+a) = 1%
where a is the amount of water you need to add.
Multiply both sides by x+a and you get
10%x = 1%x + 1%a
Subtract 1%x from both sides and get
9%x = 1%a
Divide by 1% and you get
9x = a
Thus, to make a 1 percent solution from a 10 percent solution, you need to add 9 times the current volume of the solution in water.
1:10 ratio.
There is 1 gallon of 10% solution...There is 0% saline in water...The equation is (0.1)(1) + 0x = 0.02 (x+1)...Answer is: 4 gallons. Hope I helped!!:)
To make a fraction from any percent, divide the percent by 100. 10 percent = 10/100 or 1/10 .
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
1/10
4 ml
10% = 10 parts in 100 or 1 in 10 parts. So if you make a solution, you need to make sure that whatever the amount of Clorox you use, the total amount of solution is 10 times larger. How to do this accurately depends on the measuring equipment you have available and the amount of solution you need to make.
Add 10 g to a volumetric flask and make up to the 1 liter mark.
1:10 ratio.
There is 1 gallon of 10% solution...There is 0% saline in water...The equation is (0.1)(1) + 0x = 0.02 (x+1)...Answer is: 4 gallons. Hope I helped!!:)
To make a fraction from any percent, divide the percent by 100. 10 percent = 10/100 or 1/10 .
Check what it is dissolved in first and use the same solvent for dilution. If you want to make a litre of 10% for instance, You want to dilute it 10 in 26 parts or 5 in 13. So 1 litre /13*5 is 384.6ml of 26% ammonia, and dilute to 1 litre with solvent
Take 100 grams of 5% solution and do one of the following:Mix 95 g of it with 5 grams of sugar to end up with 100 g of 10% solution, or, when you are short of sugar:Evaporate 50 grams of water from 100 g of the 5% solution to end up with 50 g of 10% solution.
Mix this 50% solution in equal quantities with water(?) to halve it's strength. So use 1 litre of the 50% solution and 1 litre of water of that's what you are diluting it with.
For normal acids, pH is most accurate. For hydrofluoric acid, pH is NOT a good indicator--a 1-percent HF solution has a lower pH than a 50-percent solution does, and a 10-percent HF solution has the highest pH of all. The range is from 3.1 (for a 1-percent solution) to 4.5 (for a 10-percent solution). HF is considered a weak acid--not all the HF molecules dissociate when the HF gas is put into water--but it's the most corrosive acid around.
1/10
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.