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How do you make 50 percent to 20 percent solution?
To make a 50% solution from a 20% solution, you need to concentrate the solution by evaporating some of the solvent. This will increase the concentration of the solute in the solution, making it 50%. Keep in mind this process should be done carefully, as it can be hazardous.
How prepare glycerol 80 percent solution?
To prepare an 80% glycerol solution, you would mix 80 parts glycerol with 20 parts water. For example, you could mix 80 mL of glycerol with 20 mL of water to make 100 mL of an 80% glycerol solution. Make sure to thoroughly mix the glycerol and water until the solution is homogenous.
Can you make 10 volume developer out of 20?
To make 10 volume developer from 20 volume developer, you can mix equal parts of 20 volume developer and distilled water. For example, mix 1 part of 20 volume developer with 1 part distilled water to create 10 volume developer.
Calculate the mole fraction of HCl in 20 percent aqueous solution?
The mole fraction of HCl in a 20% aqueous solution can be calculated by converting the percentage to a molarity concentration. Assuming the density of the solution is 1 g/mL, a 20% solution means 20g of HCl in 100g of solution. If the molar mass of HCl is 36.5 g/mol, we can calculate the molarity and then use it to find the mole fraction of HCl in the solution.
How do you get a 5 percent diluted acetic acid from a 99 percent acetic acid solution?
To make a 5% diluted acetic acid solution, you would mix 1 part of the 99% acetic acid solution with 19 parts of water (since 1 part acetic acid solution + 19 parts water = 20 parts total solution, and 1/20 = 5%). This will result in a 5% acetic acid solution.
How many ounces of 20 percent saline solution must be added to 40 ounces of a 5 percent saline solution to make a 10 percent saline solution?
NOT: 15 ounces to make 10%Correct answer:Twenty ouncesCalculus:Let it be M ounces. Then:20%*(M ounce) + 5%*(40 ounce) = 10%*(M+40 ounce)20*M + 200 = 10*M + 400(20-10)*M = 400-20010M = 200M = 20
How many gallons of a 12 percent indicator solution must be mixed with a 20 percent indicator solution to get 10 gallons of a 14 percent solution?
Let x represent the amount of 12% solution and (10-x) represent the amount of 20% solution. The equation to solve is: 0.12x + 0.20(10-x) = 0.14(10). Solving for x gives x = 4, so you need 4 gallons of the 12% solution and 6 gallons of the 20% solution to make 10 gallons of the 14% solution.
Pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
10
How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?
10 liters.
How many liters of a 20 percent solution of saline should a nurse mix with 10 liters of a 50 percent solution to obtain a mixture that is 40 percent saline?
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
If a 10 percent sugar solution is separated from 20 percent sugar solution by a selectively permeable membrane in which direction will there be net movement?
The direction will be towards the more concentrated side so the 10% solution with go towards the 20% solution in an attempt to reach equilibrium.
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
6 pints of a 20 percent solution of alcohol in water are mixed with 4 pints of a 10 percent alcohol in water solution What is the percentage alcohol in the new solution?
16%
How do you make 10 volume from 20 volume?
To make a 10 volume solution from a 20 volume solution, you need to dilute the 20 volume solution with an equal amount of water. For example, mix one part of the 20 volume solution with one part of water. This will effectively halve the concentration, resulting in a 10 volume solution.
A 280 mL solution is 20 percent salt How much water should be added to make the solution 14 percent salt?
98 mL
How many qt of pure antifreeze must be added to 3 qt of a 10 percent antifreeze solution obtain a 20 percent antifreeze solution?
0.6 of a pint.
If you have an order for 20 percent dextrose 500 ml you have 1000 ml bag of dextrose 70 percent how much of the dextrose 70 percent do you need to use to make dextrose 20 percent 500 ml?
To make a 20% dextrose solution, you need to dilute the 70% dextrose solution with water. You need to use 178.57 ml of the 70% dextrose and 321.43 ml of water to make 500 ml of 20% dextrose solution.
