First of all, if we have any two matrices of sizes mxn and pxq where m, n, p and q are natural numbers, then we must have n=p to be able to multiply the matrices. The result is an mxq matrix.
For example, a 3x1 matrix has m=3 and n=1. We can multiply it with any matrix of size 1xq. For example a 2x3 matrix can be multiplied with a 3x1 matrix which has 3 rows and 1 column and the result is a 2x1 matrix. (2x3) multiplies by (3x1) gives a (2x1) matrix. The easy way to remember this is write the dimension of Matrix A and then Matrix B. The two inner numbers must be the same and the two outer numbers are the dimensions of the matrix you have after multiplication.
For example Let Matrix A have dimensions (axb) multiply it by matrix B which has dimensions (bxc) = the result is matrix of dimensions ac. Using the trick we would remind ourselves by writing (a,b)x(b,c)=(a,c). This is technically wrong because the numbers are dimensions, but it is just a method to help students remember how to do it.
So, a 3x3 matrix can be multiplied by a 3x 1 but not by a 1,3 matrix.
How do you do it? Just multiply each entry in the first row of A by each entry in the first column of B and add the products. Do the same for the next row etc.
Many (or should I honestly say MOST) people use their fingers and go along row one and then down column one. The add the products of the entries as they do that. Then they do the same for row two and column two etc. It really does help!
(3x)(x2) = 3x3.Think of this as (3x1)(1x2). First multiply the numbers: (3)(1) = 3. next multiply the variables: (x1)(x2) = x1+2 = x3 (when you multiply powers with the same base, add the exponents)
its like 5 to the second power. 52 what ever square it is you multiply it by its self example 3 squared =3 to the power of 3= 3x3=9
A minor is a determinant and a determinant is a value associated with a square matrix.The matrix from which a minor is calculated is formed from a matrix by removing at least one of its rows or columns.We are discussing matrices of 3 rows and 4 columns. The minimum change one can make is to remove a single column. This can be done in four ways, yielding four minors. Each of these four ways yields a 3x3 matrix. There are nine minors in a 3x3 matrix.Hence, the total number of minors is 4 + 4(9)=40.
the 2 is the symbol for squared. it means that you multiply that amount of feet by itself, to get square feet. like 3x3=9, or 9= the square of 3, or 3=the square root of 9.
-3x3 - 6x2 + 189x = -3x(x2 + 2x - 63) = -3x(x + 9)(x - 7)
3 3x1=3 3x3=9
3x3=9 So, it could only be 9x1 which=9. 3x1=3 3 does not equal 9. 4x2=8 8 does not equal 9. 6x3=18 18 does not equal 9
1x3=3x3=9
the three times tables!!! 3x1=3 3x2=6 3x3=9
244 1x3=3, 3x3=9, 9x3=27, 27x3=81, 81x3=244
Put the dots in a general square outline. But make one side have 4 dots and the others have 3. Then go around the outline of the square.
3x1=3 3x2=6 3x3=9 3x4=12 3x5=15 3x6=18
(3x)(x2) = 3x3.Think of this as (3x1)(1x2). First multiply the numbers: (3)(1) = 3. next multiply the variables: (x1)(x2) = x1+2 = x3 (when you multiply powers with the same base, add the exponents)
Multiply the numerator (top) and denominator (bottom) by the same number, eg: 1/3 = 1x2/3x2 = 2/6 1/3 = 1x3/3x3 = 3/9 1/3 = 1x198/3x198 = 198/594
Multiply top and bottom by the same any whole number to get equivalent fractions: -1/3 = (-1x2)/(3x2) = -2/6 -1/3 = (-1x3)/(3x3) = -3/9 -1/3 = (-1x4)/(3x4) = -4/12 etc.
You can use matrices to find the area of the triangle.Find the three coordinates of the scalene triangle.(x1,y1)(x2, y2)(x3, y3).Then you substitute these numbers into this 3X3 matrix.x1 y1 1x2 y2 1x3 y3 1Find the determinant of this matrix.Then halve this answer and make it positive.This is your area of the triangle.The area of any triangle is: 0.5*base*perpendicular height
you start with the number three for the first one, then u keep adding three to it so 1x3=3 2x3=6 3x3=9 ect.