51*49 = -I*LI + L*LI = -LI+MMDL = IMMD (-1+2500 = 2499)
Note that in today's terms 49 and 2499 are written out in Roman numerals as XLIX and MMCDXCIX respectively but the Romans themselves would have probably wrote them out as IL (-1+50 = 49) and IMMD (-1+2500 = 2499)
Check: 51*49 = 2499
L is 50 and I is one, so LI would be 51. However, if the numerals were IL, then you would have to subtract. Then it would be 49.
51 = LI
51 = LI 51 = LI LlLI
LI stands for the number 51 in Roman numerals.
1,000 is M. 051=51 and 51 is L (for 50) I (for 1). There is no Roman numeral for 0, so 1,051 in Roman Numerals is MLI.
L is 50 and I is one, so LI would be 51. However, if the numerals were IL, then you would have to subtract. Then it would be 49.
51= LI in Roman Numerals
51 = LI
51 = LI
51 = LI 51 = LI LlLI
LI stands for the number 51 in Roman numerals.
XXXXVIIII + XXXXXI = C orXXXXVIIII + LI = C orXLIX + LI = C (probably the more correct of the versions)Another Answer:-Under todays modern rules governing the Roman numeral system nowaydays we would convert 49 into Roman numerals as XLIX but there is evidence to suggest that the ancient Romans would have added together the equivalent of 49 and 51 in either of the following formats:-A: XXXXVIIII+LI = C => 49+51 = 100B: IL+LI = C => (50-1)+51 = 100QED
The modern way of expressing the equivalent of 49 into Roman numerals is XLIX but the ancient Romans would have probably expressed it as IL or XXXXVIIII thus facilitating the speed and ease of the above calculations respectively as follows:- A: LI+IL = C => 51+(50-1) = 100. B: LI+XXXXVIIII = C => 51+49 = 100. C: LI-IL = II => 51-(50-1) = 2. D: LI-XXXXVIIII = II => 51-49 = 2.
1,000 is M. 051=51 and 51 is L (for 50) I (for 1). There is no Roman numeral for 0, so 1,051 in Roman Numerals is MLI.
LI-C
LI is 51
It is simply LI meaning 50+1 = 51