To prepare 1M Tris-HCl from a 10mM solution, you would need to dilute the 10mM solution by a factor of 100. This means you would mix 1 part of the 10mM solution with 99 parts of water to achieve a final concentration of 1M Tris-HCl.
Take 159.6 mg white, anhydrous CuSO4 or 249.7 mg blue pentahydrate (CuSO4.5H2O), dissolve in 90 mL distillled water, add 1 mL diluted ammonia (1M NH3) and finally fill up to exactly 100.0 mL with distilled water to get the final 10mM alkaline (ammoniacal) CuSO4solution.
To prepare 0.02M NaOH from 1M NaOH solution, you will need to dilute the 1M solution. Use the formula: C1V1 = C2V2, where C1 is the concentration of the stock solution (1M), V1 is the volume of the stock solution you will use, C2 is the desired concentration (0.02M), and V2 is the final volume of the diluted solution. Calculate the volume of 1M NaOH solution (V1) needed to make the desired 0.02M concentration and dilute it with water to reach the desired volume (V2).
To prepare 1M H2SO4 solution, you would need to dilute concentrated sulfuric acid (approximately 18M) by adding the appropriate amount of water. To make 1L of 1M H2SO4 solution, you would mix approximately 55.5 mL of concentrated sulfuric acid with about 944.5 mL of water in a volumetric flask while taking proper safety precautions.
To prepare 1M HCl solution from 35% HCl solution, you would need to dilute the 35% HCl with water. Use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the volume of the initial solution, C2 is the final concentration (1M), and V2 is the final volume (1 liter in this case). Calculate the volume of 35% HCl needed to achieve a 1M solution, then add water to make up the total volume to 1 liter.
To prepare a 10mM ferric chloride solution, first calculate the molecular weight of FeCl3 to determine the amount needed to achieve a concentration of 10mM. Dissolve this amount in a known volume of water or solvent to make up the final volume of the solution, ensuring thorough mixing to achieve homogeneity.
0.62 Kg/m
there are 10mm in one cm and 100cm in 1m. Times 10x100 and you get 1,000mm=1m
280 cm: 10mm = 1cm 1000mm = 1m 100cm = 1m 2800mm = 280cm
10mm=1cm 100cm=1m 1000m=1km :)
To prepare 10mM Tris solution, first calculate the amount of Tris base needed based on the molecular weight of Tris (121.14 g/mol). Weigh out the appropriate amount of Tris base and dissolve it in water to make a final volume of 1L. Adjust the pH to the desired value if necessary.
10mm=1cm 100cm=1m 1000m=1km
10mm =1cm 100cm = 1m 1000m= 1km
There is 1000mm in 1m. In 1m is broken down into 100cm and these cm are broken down into mm. For every 1cm there is 10mm. So to work out how many mm in 1m we multiply; 100 (the cm) x 10 (the mm) = 1000mm There is 1000mm in 1m. In 1m is broken down into 100cm and these cm are broken down into mm. For every 1cm there is 10mm. So to work out how many mm in 1m we multiply; 100 (the cm) x 10 (the mm) = 1000mm
2000. 10mm = 1cm 100cm = 1m 1000m = 1km
1cm = 10mm, so 4cm = 40mm. 1m = 100cm or 1000mm.
1cm=10mm 1m=100cm 1km=1000m
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.