10.82
Take 159.6 mg white, anhydrous CuSO4 or 249.7 mg blue pentahydrate (CuSO4.5H2O), dissolve in 90 mL distillled water, add 1 mL diluted ammonia (1M NH3) and finally fill up to exactly 100.0 mL with distilled water to get the final 10mM alkaline (ammoniacal) CuSO4solution.
You obtain 10 millimoles of ferric chloride and dissolve it in a liter of water.
1.21 g Tris-HCl, QS water to 1L. Scale appropriately.
40 grams, this is the 1M NaOH standard laboratory solution.
Dilute 1M Tris 1:100
0.62 Kg/m
there are 10mm in one cm and 100cm in 1m. Times 10x100 and you get 1,000mm=1m
280 cm: 10mm = 1cm 1000mm = 1m 100cm = 1m 2800mm = 280cm
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
10mm=1cm 100cm=1m 1000m=1km :)
10mm=1cm 100cm=1m 1000m=1km
10mm =1cm 100cm = 1m 1000m= 1km
There is 1000mm in 1m. In 1m is broken down into 100cm and these cm are broken down into mm. For every 1cm there is 10mm. So to work out how many mm in 1m we multiply; 100 (the cm) x 10 (the mm) = 1000mm There is 1000mm in 1m. In 1m is broken down into 100cm and these cm are broken down into mm. For every 1cm there is 10mm. So to work out how many mm in 1m we multiply; 100 (the cm) x 10 (the mm) = 1000mm
10.82
2000. 10mm = 1cm 100cm = 1m 1000m = 1km
1cm = 10mm, so 4cm = 40mm. 1m = 100cm or 1000mm.