Make a 1 to 100 dilution of the original 1000 ppm solution. That is take 1 ml and dilute to 100 ml, or take 10 ml and dilute to 1000 ml. This will give you a 10 ppm solution.
Assuming that 100 ml of 1 ppm solution has to be produced,
Volume required from 1000 ppm solution = 1 ppm x 100 ml / 1000 ppm
= 0.1 ml
thus, 0.1 ml volume should be measured from 1000 ppm solution and transferred into a 100 ml volumetric flask. Then the solvent used in preparing the solution should be added upto the mark of the volumetric flask to prepare 1 ppm solution.
The equation C1 x V1 =C2 x V2 can be used to prepae any solution from a standard solution.
C1 and C2 are concentrations of the two solutions. V1 and V2 are volumes from the two solutions.
To take 2.5 ml from the 1000ppm solution and dilute to 100 ml.
Preparation of 10ppm solution from 100ppm solutin
First you dilute it 10 times. You get solution of 100 ppm. Then dilute it 5 times. You get solution of 20 ppm.
Make a 1 to 100 dilution of the original 1000 ppm solution. That is take 1 ml and dilute to 100 ml, or take 10 ml and dilute to 1000 ml. This will give you a 10 ppm solution.
10000000
10095445.4554
how to prepare 1000 ppm solution of nickel carbonate
dilute it 1 in 5000. likely best done with a serial or step dilution
You prepare a primary solution then dilute portion of your solution down to the required concentration. For example, you want a 10 ppm salt solution (10 mg/L), you dilute 1 g of salt in 1 L of water you get 1000 ppm salt solution. You take 10 ml of your salt solution (0.01 g salt in 10 g) and add in additional 980 ml of water then you get a 10 ppm weight solution.
1 ppm is 1 mg per litre so you need to weigh out the amount of zinc sulfate that contains 10mg i.e 0.01g SO4 which is 287.4/32 =8.98125g ZnSO4-7H2O and add to a 1 lt volumetric flask and dilute with water to 1 litre.
1000 ppm Cl- = 1.0 gram per liter Cl- = 1.0 * [58.5 (gNaCl/mole NaCl)] / [35.5 (gCl-/mole NaCl)] = 1.65 g/L NaCl
how to prepare 1000 ppm solution of nickel carbonate
Parts per million (ppm) is the same as mg/L. So, dissolve 5 mg of NaOH in 1 L of water and viola!
dilute it 1 in 5000. likely best done with a serial or step dilution
5ml of the 1000 ppm solution in 95ml distilled water gives a 500ppm solution
You prepare a primary solution then dilute portion of your solution down to the required concentration. For example, you want a 10 ppm salt solution (10 mg/L), you dilute 1 g of salt in 1 L of water you get 1000 ppm salt solution. You take 10 ml of your salt solution (0.01 g salt in 10 g) and add in additional 980 ml of water then you get a 10 ppm weight solution.
1 ppm is 1 mg per litre so you need to weigh out the amount of zinc sulfate that contains 10mg i.e 0.01g SO4 which is 287.4/32 =8.98125g ZnSO4-7H2O and add to a 1 lt volumetric flask and dilute with water to 1 litre.
1 ppm HCl in aqueous solution would have a pH of around 6.
What volume of this solution do you desire? Let's say you want to make 1 liter of such a solution. You would weigh out 1 gram (1000 mg) of NaCl and dissolve it in enough water to make a final volume of 1 liter (1000 ml). Since 1000 ppm means 1000 mg/liter, this is how you make 1 liter of that solution. For larger or smaller volumes, adjust appropriately.
1000 ppm Cl- = 1.0 gram per liter Cl- = 1.0 * [58.5 (gNaCl/mole NaCl)] / [35.5 (gCl-/mole NaCl)] = 1.65 g/L NaCl
Just take 3 grams and add this to 1000 litres (= 1,000 kg = 1,000,000 (million) grams)
Dear friends, PPM means Part Per Millions, So It means if you takes 1 gm of Solid Chloride Ions and Dissolve it in D. water. The Current Stock solution is having 1000 PPM of Chloride Ions. NOW if you want lesser PPM solution from this stock Solution, follows below rule- Required PPM Solution (A) ---------------------------------- X Required Volume of A PPM solution === Nos. of mL Stock Solution PPM (1000) to be taken from this stock solution and add in required Volume. Dr.P.Khemariya Research Scientist R&D dr.p.khemariya@gmail.com
Assuming that you are referring to PPM as (parts per million), you can prepare a report on the solution, depending on the different ingredients that are involved and quantity of each substance present.