How do you solve a dilution problem in Chem?

The key formula for solving a dilution problem is M1V1=M2V2 (alternately, MAVA=MBVB)

where concentration is M (measured in Molars, a unite of concentration-->Molars=moles solute/Liters solution) and the volume of solution is V.

M1V1 represents the inital conditions (pre-dilution), and M2V2 denotes the final conditions (post-dilution).

Plug in the three values you know to find the fourth value, which you are solving for.

Ex.

750mLs of a 0.5 M NaC2H3O2 solution is diluted with 250mL of H2O. What is the new concentration of NaC2H3O2?

Answer:

(0.5M)x(.750L)=(MB)x(.750L+.250L)

0.375ML=(MB)x(1L)

MB=0.375M