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√(6x) - 3 - 3√x = 1

√(6x) -3√x = 4

√x = 4/(√6 - 3) = -4(√6 + 3)/3 = 16/9*(15+6√6) = 16/3*(5+2√6) = 52.8, approx.

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10y ago
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Q: How do you solve the square root of 6x minus 3 minus the 3 times the square root of x equals 1?
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