2•(p-q)
The difference of p and q can be written : p - q Twice the difference is therefore 2 x (p - q) which can also be written as 2(p - q) OR 2p - 2q. Consequently you can create another variable (say) y and make this equal to twice the difference of p and q by simply writing, y = 2(p -q)
Qx2+4
P! / q!(p-q)!
4(QxP)
If B is between P and Q, then: P<B<Q
The difference of p and q can be written : p - q Twice the difference is therefore 2 x (p - q) which can also be written as 2(p - q) OR 2p - 2q. Consequently you can create another variable (say) y and make this equal to twice the difference of p and q by simply writing, y = 2(p -q)
The sum of p and q means (p+q). The difference of p and q means (p-q).
If p then q is represented as p -> q Negation of "if p then q" is represented as ~(p -> q)
A rational number can be expressed as a ratio in the form, p/q, where p and q are integers and q > 0.
If you mean, (by rational form), in the form "p/q", let p= -2 and q = 1
Assuming the angles are expressed in degrees: P = 2Q -3° (because "angle P is three less than twice the measure angle Q") P + Q = 180° (because they are supplementary angles) P+Q = 2Q - 3° + Q = 3Q -3° = 180° 3Q = 183° Q = 61° P = 2∙61° -3° = 122° - 3° = 119° If the angles are expressed in radians, the math is similar except you start with P = 2Q - 3 and P+Q = π yielding P = 2π/3 -1 and Q = π/3 +1
An irrational number cannot be expressed as a ratio in the form p/q where p and q are integers and q > 0. Integers can be.
Qx2+4
We can not provide a specific value as an answer to this question as both p and q are variables and their value is unspecified.However we can write this as:-8(p + q).We can multiply out the bracket to get:-8p + -8q.This is as far as we can answer this question unless the values of p and q are known.-8(p + q) = -8p + -8q
The "p" in "p's and q's" is believed to stand for "pints" and "q" for "quarts," referring to minding one's manners or being polite and well-behaved.
In algebra, you could write it as simply 'pq'.
coefficient