You have for an Ideal Gas:
PV = mRT/M
( P2 ) ( V2 )/ (T2 ) ( m2 ) = ( P1 ) ( V1 ) / ( m1 ) ( T1 ) = R/M = Constant
V2 = ( V1 ) ( P1 /P2 ) ( T2/T1 ) ( m2 /m1 )
You have :
( P1 / P2 ) = 1.00
( T2 / T1 ) = 1.00
( m2 / m1 ) = 2.00
V2 = ( V1 ) ( 1.000 ) ( 1.000 ( 2.000 ) = ( 2.000 ) ( V1 ) <-------
Doubling the mass will also double the volume .<----[ Answer ]---
Pressure and volume have an indirect relationship, so when you increase the pressure the volume will similarly decrease. By doubling the pressure, you will roughly cut the volume in half.
This is also doubled.
Pressure increases as volume increases, granted the container stays the same.
It would be half of the original volume. As you reduce the volume the pressure would increase and at half the original volume the pressure would be doubled.
The volume of the container is increased.
20psi
According to Charles' Law: Volume of a gas increases as temperature inceases. But if the gas is contained in a rigid container then the volumme cannot increase, but the pressure will.
the volume doubles
Pressure increases as volume increases, granted the container stays the same.
In a perfectly flexible and expandable container (pressure is constant) the volume of an ideal gas will double as the absolute temperature doubles. For a non-ideal gas and non-perfect container, your results will vary but will always be somewhat less than double.
In a perfectly flexible and expandable container (pressure is constant) the volume of an ideal gas will double as the absolute temperature doubles. For a non-ideal gas and non-perfect container, your results will vary but will always be somewhat less than double.
If the volume stays the same, the pressure will decrease.
In a small volume container the pressure is higher.
Assuming the volume is kept constant, the pressure will also decrease in this case.
If the volume of a container of air is reduced by one half the partial pressure of the oxygen with in the container will be doubled. If the volume of a container of gas is reduced, the pressure inside the container will increase.
If you increase the volume of the container, and not the gas itself, then the pressure decreases. If you increase the volume of the gas, and not the container, then the pressure increases.
It would be half of the original volume. As you reduce the volume the pressure would increase and at half the original volume the pressure would be doubled.
If you double the amount of gas in the same volume you will double the pressure.
Placing a rock in a container does not alter the volume of the container, although it does occupy some of that volume.