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no. it affects the period of the cycles.
The length of the pendulum, the angular displacement of the pendulum and the force of gravity. The displacement can have a significant effect if it is not through a small angle.
At greater gravitational force, the frequency (the number of cycles per second) will be higher.
swings = cycles x time ; it is a direct relationship with time
Length of the rope, speed at which the pendulum is moving, friction between the rope and the air, the rope and its suspension point, and within the rope itself.
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frequency ..... A+
The period of the pendulum can be influenced by the local magnitude of gravity, by the length of the string, and by the density of the material in the swinging rod (which influences the effective length).It's not affected by the weight of the bob, or by how far you pull it to the side before you let it go.
frequency ..... A+
The shorter the pendulum the more swings you get.
There's no relationship between the length of the pendulum and the number of swings.However, a shorter pendulum has a shorter period, i.e. the swings come more often.So a short pendulum has more swings than a long pendulum has in the same amountof time.
While we consider the pendulum experiment, we consider so many assumptions that the string is inelastic and there is no air friction to the movement of the bob. With all these, we derive the expression for the time period of the pendulum as T = 2 pi sqrt (l/g) Here, in no way, mass of the bob comes to the scene. So, mass of the bob does not have any effect on the time period or its reciprocal value, namely, frequency. ie number of swings in one second.