None. The speed of sound in air doesn't depend on its frequency.
(If it did, then a person yelling to you from a distance would sound all garbled, because
each frequency in his voice would reach your ear at a slightly different time.)
The wavelength is reduced to half of its original length, and the ear perceives the pitch of the sound as having risen one octave.
The wavelength of the sound waves halves, but the speed remains the same.
sound wii be drease by 2 times and frequency increase by 2 times.
The frequency is the reciprocal of the period. If the period is doubled, the frequency will change by a factor of 1/2.
INCREASE BY 6 dB.
Light intensity is inversely proportional to the square of the distance: I = k/d2
As light gets farther from the source, the same amount of light spreads out over a larger area.
The intensity reduces in proportion to the square of your distance from the source.
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
The intensity of a sound will decrease according to an inverse square law.
The intensity increases by a factor of 4-APEX
- 6 dB is incorrect. It will decrease by 12 dB.
Light intensity is inversely proportional to the square of the distance: I = k/d2
As light gets farther from the source, the same amount of light spreads out over a larger area.
The intensity reduces in proportion to the square of your distance from the source.
The intensity of a sound will decrease according to an inverse square law.
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
physics
For sound intensity (acoustic intensity) we use in the free field (direct field) the inverse square law = 1/r². I1 and r1 belong to the close distance and I2 and r2 belong to the far distance.I2 = I1 * (r1/r2)²I2 = I1 * (1/3)² = I1 / 9Three times farther away gives one ninth the sound intensity of the close sound intensity.
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
the waves spread out over a larger areathe waves are absorbed by the medium as they pass through itthe waves are being scattered by irregularities in the medium and don't all proceed forwardetc.
It's an inverse-square law - for instance, double the distance, and the intensity will be reduced by a factor 1/4.This assumes that there is nothing absorbing the light (for instance, fog); if there is, the intensity in the above example will of course be even less than 1/4 the original intensity.