I expect the gravitational force between them will become
four times as great as it was originally.
The gravitational force between two bodies is proportional to the product of the two masses. Original masses = 'A' and 'B' Original force = (konstant) times (A B) New masses = (A/2) and (2B) New force = (konstant) times (A/2)(2B) = (konstant) times (2AB/2) = (konstant) times (AB) = same as original. Note: The force is also inversely proportional to the square of the distance between their centers of mass. You only asked about changes in mass, so this work only considered the masses. The work, and the answer derived, assume that the distance between the bodies doesn't change.
According to the universal law
F=(Gm1m2)/R2
If we let
m1<m2 ;
then m1 will accelerate towards m2 with g and the force, F is then given by Newton's 2nd law as;
F=m1g
and
m1g=(Gm1m2)/R2
g=(Gm2)/R2
thus doubling m2 would double g
i.e. 2g=2(Gm2)/R2
the lighter body would accelerate at twice the initial acceleration by doubling m2, towards the heavier body. on the other hand it would descelerate by half if m1 was to be doubled.
The gravitational force will decrease to 0.125 = 1/8 = 12.5% of its original value.
I expect the gravitational force between them will become
four times as great as it was originally.
When the distance between the centers of two objects is doubled, the gravitational forces between the objects are reduced by 75% .
If one of the two masses doubles but the distance between them remains unchanged,then the magnitude of the gravitational force between them is also doubled.
it would reduce by two squared, which is 4
The gravitational force has a 1/r2 dependence, so if you double the distance, the force is decreased by a factor of 4.
The effect of dubling the massesa and halving the distance is to increase the gravitational force by a factor of 16.
When the distance between the centers of two objects is doubled, the gravitational forces between the objects are reduced by 75% .
Its pull on the earth would be 25% as strong.
Gravitational force is inversely proportional to the square of the distance. Therefore, double the distance = 1/22 = 1/4 the force.
If one of the two masses doubles but the distance between them remains unchanged,then the magnitude of the gravitational force between them is also doubled.
it would reduce by two squared, which is 4
The sun would have 1/4 as much pull on the earth.
The gravitational force has a 1/r2 dependence, so if you double the distance, the force is decreased by a factor of 4.
The effect of dubling the massesa and halving the distance is to increase the gravitational force by a factor of 16.
If the gravitational force decreases according to the square of the distance, then if the distance is doubled the force becomes one forth of what it was. So if you doubled the the distance between the two objects then they would have a gravitational force of 125 Newtons. That happens because 2 squared is 4 and 500 divided by 4 is 125.
The gravitational force between two objects is inverseley proportional to the square ofthe distance between them.If the distance is doubled, then the force falls to [ 1/22 = 1/4 ] of the original force.If the original force was 16 units, then the new force is (16/4) = 4 units after the distance doubles.
If the mass of both of the objects is doubled, then the force of gravity between them is quadrupled; and so on. Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.
The moon might escape it's orbit and become a moon of another planet.