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The vertical component of the projectile's motion is uniformly accelerated, no matter what the angle of launch was.
its upward at some specified angle
Assuming the angle is the angle the initial trajectory makes with the ground, that it's launched with the same speed in both cases, that it's launched from an initial height of zero, that it stops dead as soon as it touches the ground and doesn't bounce or roll, and that we can neglect air resistance (sorry for all that detail, but it does matter)... Both projectiles will end up with the same net displacement, though the 60 degree projectile will have taken a longer path to get there.
angle of projection,initial velocity and gravitational acceleration
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
Some of the factors that determine the movements of a projectile include: air resistance, force of gravity, initial launch velocity, the angle a projectile was launched at, and the objects initial elevation.
Get the value of initial velocity. Get the angle of projection. Break initial velocity into components along x and y axis. Apply the equation of motion .
The vertical component of the projectile's motion is uniformly accelerated, no matter what the angle of launch was.
The half maximum range of a projectile is launched at an angle of 15 degree
its upward at some specified angle
In a perfect system, with no air resistance, the arc that a projectile moves through is a parabola. The shape of the parabola is dependent of various parameters including the initial velocity (speed and angle of launch) as well as the prevailing gravity. It could also describe a circle if the launch criteria are just right for the gravity, such as a satellite orbiting the Earth.
if a body is thrown having initial velocity and make angle with ground this body is known as projectile and the way is calle trajectory
Assuming the angle is the angle the initial trajectory makes with the ground, that it's launched with the same speed in both cases, that it's launched from an initial height of zero, that it stops dead as soon as it touches the ground and doesn't bounce or roll, and that we can neglect air resistance (sorry for all that detail, but it does matter)... Both projectiles will end up with the same net displacement, though the 60 degree projectile will have taken a longer path to get there.
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
look up naked penus Wow. Some people have nothing to do but waste time. There is no way to answer that as asked A very general answer is, whatever angle will cause the projectile to land where you want it to.
Launch angle means the angle at which a rocket or object is place as it is being sent into the air. This determines its initial flight and is particularly important for rockets which are entering orbit.
yes it does. you see if you have it set up at a a 90 degree angle it will go further than it would of a 10 degree angle A projectile leaving the ground at an angle of 45 degrees will attain the maximum range. Fire it straight up and it will fall back to its launch location (wind effects etc. ignored). Fire it horizontally and it will hit the ground very much the same time as if it was dropped from its launch platform at the same time. That would not be very far.