That completely depends on the shape of the object. It should be easy to find a lead sinker and a piece of cloth with the same weight as the sinker. Drop them both out of a second-floor window, and you'll see that the effects of air resistance have nothing to do with the object's weight, but a lot to do with its shape.
If it starts from rest and air resistance is ignored,
it would fall 19.6 meters.
After one second, an object will have fallen a distance of 1/2 × 9.8 × 12 = 4.9 meters. But I don't exactly know how far it will have fallen in a quarter of a second. :( Sorry!
formula
d=16t^2
d=16x1x1
16 feet or about 9.8 m
A handy formula for distance covered from rest with constant acceleration in time 'T':D = 1/2 a T2D = (1/2) (9.8) (5)2 = 122.5 meters
If it leaves your hand with a vertical velocity of 9.8 m/sec, its speed drops to zero after 1 second and it begins to fall. After one more second, it returns to the height where it left your hand. (We don't know how much farther it has to fall to hit the ground.)
Assuming the object is falling near the surface of the Earth and neglecting air resistance, the object will fall approximately 4.9 meters in 1 second. This calculation is based on the acceleration due to gravity, which is approximately 9.8 meters per second squared.
Response time of the sensor.For 1 sec how many times you can sense the object.
If it leaves your hand with a vertical velocity of 9.8 m/sec, its speed drops to zero after 1 second and it begins to fall. After one more second, it returns to the height where it left your hand, and is falling at 9.8 m/sec. (We don't know how much farther it has to fall to hit the ground, so we don't know how much more speed it will pick up the rest of the way.)
32.2 feet.
A handy formula for distance covered from rest with constant acceleration in time 'T':D = 1/2 a T2D = (1/2) (9.8) (5)2 = 122.5 meters
not very far
If it leaves your hand with a vertical velocity of 9.8 m/sec, its speed drops to zero after 1 second and it begins to fall. After one more second, it returns to the height where it left your hand. (We don't know how much farther it has to fall to hit the ground.)
if the object is falling straight then the force from which the ball is falling toward earth is the gravitational force of the earth that is 9.81 m/sec2. so by formula we have, speed=distance/time ,also distance=speed*time here if the ball is freely falling that is no external force is applied on ball then the s=gravitational pull and time given is 2 sec there for in 2 sec the object fall ; d=9.8 m/sec2 *2 sec d=18.36 m(approx) if any other suggestion then do tell me I am no expert but I do believe the correct formula to use for this situation is d=1/2 gt2. The formula above will only work for example if you are traveling at a constant velocity in a car of 9.8 meters per second. You need to take into account that an object in free fall is constantly accelerating and not in a constant motion. The correct answer should be closer to 19.6 m.
You also need to know how long it travels. Just multiply the speed with the time. For instance, if the object moves at 70 feet/sec during 1 minute, you multiply: 70 ft/sec x 1 minute = 70 ft/sec x 60 sec. = 4200 feet.
just over 3 seconds. 32.2 ft/sec/sec not calculating in acceleration to terminal velocity. the 1st sec = 1 * 32.2ft + the 2nd sec = 2 * 64.4ft + the 3rd sec = 3 * 96.6ft = almost 200ft
Assuming the object is falling near the surface of the Earth and neglecting air resistance, the object will fall approximately 4.9 meters in 1 second. This calculation is based on the acceleration due to gravity, which is approximately 9.8 meters per second squared.
1 sec after its happens.
Response time of the sensor.For 1 sec how many times you can sense the object.
1 min = 60 sec 1 hour = 60 min = 60 × 60 = 3600 sec → 1 sec = 1/3600 hr distance = speed × time = 45 mph × 1 second = 45 mph × 1/3600 hr = 45 × 1/3600 miles = 1/80 mile = 1 chain = 22 yards = 66 feet
If it leaves your hand with a vertical velocity of 9.8 m/sec, its speed drops to zero after 1 second and it begins to fall. After one more second, it returns to the height where it left your hand, and is falling at 9.8 m/sec. (We don't know how much farther it has to fall to hit the ground, so we don't know how much more speed it will pick up the rest of the way.)