If the tree is T ft high, then
T/21 = 8/3 so that T = 21*8/3 = 56 feet.
The shadow:object ratio is 1:1 so the tree is 63 feet high.
27.3 feet
3.4
You need more information to solve this problem. The length of a shadow depends on the angle of the sun which depends on the time of day.
If the angle of elevation is 32 degrees then using the tangent ratio in trigonometry the height of the tree is 18.75 feet rounded up to two decimal places
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
50 feet
5.5/8 = x/20 x=5.5*20/8 = 13.75 feet
15 feet high
It works out as 12 feet and 4 inches in height
The shadow:object ratio is 1:1 so the tree is 63 feet high.
(12 / 5) × 33 = 79.2 feet high Divide the pole shadow by the pole height: (12 / 5) = 2.4 feet Times the 2.4 by the tree shadow of 33 feet: 2.4 x 33 = 79.2
We can not tell because we do not know how straight the tree is or if the ground is perpendicular or level.
27.3 feet
17.45 feet.
The man is twice as high as his shadow. Therefore, the tree must also be twice as high as its shadow, which would make the tree 40 feet tall.
The man is 5.96 feet tall and the lamp is 17.88 feet high.