you need its drag coefficient(dc), its rolling resistance(rr), its mass(m)in kg, its velocity(v) in m/s.
(v^2*dc )+rr (result in newtons), then this force will tend to decelerate the train d=f/m, but as you slow this force diminishes , the deceleration also, using small increments of time , you can approximate, the answer, maybe calculus can be applied
You have to be traveling at about 80.67 feet per second.
At 60 mph you are traveling at 88 feet per second.
It takes about 1 (0.97) second.
Its speed is 6 feet per second. Its velocity is 6 feet per second in whatever direction it's going.
102.7 feet every second at 70mph
132 fps
At 180mph you are traveling at 264 feet per second.
At 60 mph you are traveling at 88 feet per second.
You have to be traveling at about 80.67 feet per second.
It takes about 1 (0.97) second.
Jesse is traveling at 154 feet per second.
1. If they trains are traveling away from each other he observes the train at a relative velocity of 112 mph (63 + 49) 2. To get the answer we must multiply the velocity times the time. 3. The hardest part about this problem are the units. 4. Convert mph to feet per sec, then multiply times 4.5 sec to get the answer in feet. Answer= 739.2 feet
51.3333 feet per second
44 feet per second.
14.66 feet per second.
At 200 mph, the train is moving at 293.3 feet per second.
It is traveling at about 58.66 feet per second.