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How long is the diagonal in a rectangle if the sides are a and b?
Wiki User
∙ 13y ago
if the sides are 'a' and 'b' then you can call the diagonal 'c'. all you have to do is a2 + b2 = c2. once you fin out what 'a2 + b2' is just root it and you will have 'c', your diagonal.
Wiki User
∙ 13y ago
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Is a diagonal line through a rectangle equal to the vertical and horizontal sides?
No. The diagonal through a rectangle can be computed via the Pythagorean theorem: c2 = a2 + b2 where c is the diagonal length and a and b are the horizontal and vertical lengths of the rectangle.
How do you work out the diagonal line in a rectangle size 5cm x 10cm?
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
How do you prove that the diagonals of a rectangle are congruent using vectors?
If the vectors emanting from one corner of the rectangel are called a and b then. (a) + (b) = one diagonal (a) + (-b) = the other diagonal and |(a) + (b)| = |(a) + (-b)| (the absolute value of the diagonal's scalars are equal)
How do you get the length of a rectangle corner to corner?
This length (diagonal) = sq.rt ( l2 + b2 ) where 'l' is length of the rectangle and 'b' is the breadth of the rectangle.
How do you work out the diagonals of a rectangle?
Well, you know that in order to classify a shape as a rectangle all of the sides have to be congruent or 90 degrees. If you draw the diagonal of that rectangle, you come up with two right triangles. So you can use the Pythagorean theorem (a squared+b squared=c squared) to find out the diagonal. Ex: If the length=4, and width=3, then diagonal=5, because 4 squared+3 squared=5 squared.
Is a diagonal line through a rectangle equal to the vertical and horizontal sides?
No. The diagonal through a rectangle can be computed via the Pythagorean theorem: c2 = a2 + b2 where c is the diagonal length and a and b are the horizontal and vertical lengths of the rectangle.
A rectangle is 3 meters wide and 10 meters long how long is the diagonal of the rectangle?
To find the length of the diagonal in a rectangle, use the formula for calculating the hypotenuse of a right triangle: a² = b² + c². a² = 3² + 10² a² = 9 + 100 a² = 109 a = 10.44 m
How do you work out the diagonal line in a rectangle size 5cm x 10cm?
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
How do you prove that the diagonals of a rectangle are congruent using vectors?
If the vectors emanting from one corner of the rectangel are called a and b then. (a) + (b) = one diagonal (a) + (-b) = the other diagonal and |(a) + (b)| = |(a) + (-b)| (the absolute value of the diagonal's scalars are equal)
How do you get the length of a rectangle corner to corner?
This length (diagonal) = sq.rt ( l2 + b2 ) where 'l' is length of the rectangle and 'b' is the breadth of the rectangle.
How do you work out the diagonals of a rectangle?
Well, you know that in order to classify a shape as a rectangle all of the sides have to be congruent or 90 degrees. If you draw the diagonal of that rectangle, you come up with two right triangles. So you can use the Pythagorean theorem (a squared+b squared=c squared) to find out the diagonal. Ex: If the length=4, and width=3, then diagonal=5, because 4 squared+3 squared=5 squared.
What is the length of a rectangle whose diagonal is 32 inch?
The diagonal of a rectangle does not provide enough information to determine the length of the rectangle. Let L be any real number such that 32/sqrt(2) < L < 32. let B = sqrt(32^2 - L^2) Since L < 32 the above square root exists, and since L > 32/sqrt(2), B < L. So the rectangle with sides of L and B will have a diagonal of 32 inches. But L is any of an infinite number of possible real numbers. Therefore there are infinitely many possible solutions.
What is the length of the diagonal that bisects the rectangle into two triangles?
It is sqrt(L2 + B2) where L and B are the length and breadth of the rectangle.
If sides of rectangle A to rectangle B has ratio 4 to 5. What would the perimeter of rectangle A if the rectangle B has a perimeter of 100 What about area of Rectangle A if the area of rectangle B is?
The perimeter of rectangle A would then be 80 because 80 to 100 is 4 to 5 simplified and the area of triangle A would depend on the sides and area of rectangle B which have not been given.
The area of a rectangle is 126 square inches and two of its sides are 18 inches longhow long are the other two sides?
Area of rectangle = Length * Breadth 126 = 18 * B => B = 126/18 = 7 inches.
Is a rectangle a square or a square a rectangle?
A square is rectangle with all its sides are equal in length. The rectangle has: (a) opposites sides are parallel. (b) opposite angles are equal
What is length of diagonal line in a rectangle 34 feet by 30 feet?
The diagonal line forms two triangles, each with one side 34 feet long and one side 30 feet long. Use Pythagorean Theorem to find the length of the diagonal line which is the hypotenuse of the triangles. a^2 + b^2 = c^2 Where a and b are the sides of the triangle and c is the hypotenuse. (34)^2 + (30)^2 = c^2 1156 + 900 = c^2 2056 = c^2 45.34 = c So, the diagonal line is 45.34 feet.
