A 1930 silver dollar weighs approximately 26.73 grams. A gallon of water weighs about 3,785 grams, which means roughly 141 silver dollars (3,785 grams ÷ 26.73 grams per dollar) would fit in a gallon. However, this is a theoretical calculation based on weight, and actual packing may vary due to the coins' size and arrangement.
To determine how many Morgan silver dollars can fill a five-gallon bucket, we first need to calculate the volume of a single Morgan silver dollar. The diameter of a Morgan silver dollar is approximately 38.1 mm, with a thickness of around 2.4 mm. Using these measurements, we can calculate the volume of a single coin. Once we have the volume of a single coin, we can then calculate how many of these coins would fit into a five-gallon bucket, which has a volume of 18,927 cubic centimeters.
tom has 39 silver dollars
That's like asking how many minutes are in a yard, or how many miles in a pound, or how loud is 72 degrees. It's an incompatible measurement comparison.
39
20 - 33 gallon
if a silver dollar is 90% silver it would take 1 and 1/10th silver dollars to make an ounce of silver
silver dollars should all be 1 ounce give or take a few grams
How many Morgan silver dollars in your 20th Century Silver dollar series? How many total coins in your 20th Century Silver Dollar Collection!
423,515
around 322
Dont know
1000