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There are 280 of them.
45 of them.
There are 2700 digits.
If by "between" you mean "between but not including", then the answer is 9999 - 999 - 1 = 8999.If on the other hand, you mean to include both 9999 and 999, then the answer is 9999 - 999 + 1 = 9001.
there are 999 - 100 + 1 = 900 positive triple digit positive integers, between 100 and 999.(e.g. there are 102 - 100 + 1 = 3 triple digit integers between 100 and 102,namely 100, 101 and 102.)multiply that by 2 to take in consideration of the negative integers,you have 1800 triple digit integers.
998
they would be of the format XYXwhere X varies from 1 to 9and Y varies from 0 to 9 for each value of X.for a total of 9 * 10 combinations = 90*This Assumes that you wanted to include 999 as one of your answers How ever it could be argued (correctly) that it is not between 100 and 999*
Well.. There are 899 999 numbers between 100,000 & 999 999, so basically pick any6 positive whole numbers (1-9) and mix them up. Do this three times, ta da!
1
There is only one 7. Whether it's between 1-999, or between 1-999,999,999. Now, if the question was how many numbers that contains 7 in it (i.e., 17, 27, 70, 750) I am not sure. I believe it is 280.
There are 900 hundred positive three digit numbers.My previous answer was wrong! Argh.The smallest three-digit number is 100. ( 999 + 1 ) - 100 = 900And the original answerer was correct.
997