If the transformer is three phase the calculation is I = 30,000 / 1.73 E.
If the transformer is single phase the calculation is I = 30,000 / E.
(Where I = current and E = secondary voltage)
It is important to note the voltage in the first formula is line to line (typically how it is specified in three phase power systems), and the second formula it is line to neutral.
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
This typically has to do with how many amps you can safely pull from the secondary of the transformer.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
There are actually three pieces to this puzzle - resistance. And you're missing that one.
for three phase the calculation is 30,000 = 1.73*V*I - simple as that. For single Phase the calculation is 30,000 = V*I - simple as that It is important to note the voltage in the first line is Line to Line (typically how it is specified in three phase power systems), and the second line it is Line to neutral. A 30KVA transformer is the same as 30,000VA to find out the Amps you need to divide the voltage if the transformer is single phase for example: 30,000VA / 480V = 62.5 Amps The calculation for a 3 phase transformer is the VA / voltage / 1.73 for example: 30,000VA /480V / 1.73 = 36.12 Amps
21.4 amps, 2100 wattsManoj
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
This typically has to do with how many amps you can safely pull from the secondary of the transformer.
2.083 amps
30 amps
To answer this question a voltage must be given.
The amps that a four gauge wire will handle will depend with the thickness of the wire. If the wire is thin, the four gauge will handle 95 amps.
The transformer itself does not pull current. Whatever you connect to the transformer pulls current. Whatever the output voltage of the transformer is, divide that into 600 and you get maximum current possible without burning up the transformer. At 24V that's 25 amps.
It depends on the rated voltage of its secondary.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
Rephrase your question, as it doesn't make any sense. If the primary side of the transformer is 480 volts 3 phase, this transformer can be supplied from a breaker as big as 180 amps. If 480 volts 3 phase is your secondary then you can supply up to 180 amps to your loads.
To determine how many amps a battery can handle, this information should be on the battery itself. You can also get a battery tester to determine amperage.