The terminal strip's rating is 15 amps at 600 volts. It does not matter what the voltage is up to 600 volts, the maximum amperage allowed on the strip is 15 amps. It could be 15 amps at 12 volts or 15 amps at 600 volts or any voltage in between.
When you multiply amps x volts the product is watts. Using this formula W = Amps x Volts should give you your answer.
When they give you WATTS the also give you VOLTS. Using some very simple math you can then figure out AMPS. WATTS = Amps x Volts
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
The voltage has nothing to do with the capacity of a wire to handle current. A #12 copper wire with an insulation factor of 60, 75 or 90 degrees C is rated at 20 amps.
I = W/E. Current is equal to Watts divided by Volts. 1500/120 = 13 amps. A #14 is rated at 15 amps. A conductor can only be loaded to 80% for a continuous load so 80% of 15 equals 12 amps. Too small for the 1500 watt load. A #12 conductor is rated at 20 amps times 80% equals 16 amps for a continuous load. To answer your question, no, a #16 conductor will not handle a 1500 watt load.
When you multiply amps x volts the product is watts. Using this formula W = Amps x Volts should give you your answer.
A 1,000 watt inverter giving 110 volts is rated at 9 amps.
No. Your power supply must be able to supply rated voltage (12 volts) and rated current (3 amps).
Breakers and other electrical equipment are rated in voltage so you know what voltage they can withstand. The breaker could fail and start a fire if you apply a higher voltage than it is rated for. Breakers are actually rated in amps (current in excess of this will trip it), interrupting rating (how many amps the breaker can handle during a short circuit) and in volts (is the difference of potential or the pressure that is pushing the current). The breaker I am looking at is rated for 15 amps, 10,000 amps interrupting rating and 120/240 volts.
A # 14 copper conductor will be fine to carry 8 amps at 120 volts. This size conductor is rated at 15 amps.
When they give you WATTS the also give you VOLTS. Using some very simple math you can then figure out AMPS. WATTS = Amps x Volts
Fuses are rated in Amps. Although the physical size of a fuse is to do with volts; the further the terminals are apart the less likelihood there is of 'sparkover' between them.
Volts, amp hours an cold cranking amps.
6 AWG will handle 50 amps with a voltage drop of about 4 volts. If you go to 4 AWG and limit to 50 amps your voltage drop will be 2.5 volts.
You would need to use a #12 copper conductor to continuously draw 14 amps at 120 volts.
The voltage has nothing to do with the capacity of a wire to handle current. A #12 copper wire with an insulation factor of 60, 75 or 90 degrees C is rated at 20 amps.
Volts * Amps = Watts 120 Volts * 12.5 Amps = 1500 Watts Doesn't sound like a good idea.