There are 6 atoms of H20 in CoCI2 x 6H20. I'm not sure, but there are also 1 Co atom and 2 CI atoms since it's Co and CI 2 <----- Subtext represents how many of the atoms there are for that element, in this case, CI. Hope my answer's right >_-
Glucose and oxygen producing carbon dioxide water and energy C6H12O6 + 6O2 -------> 6CO2 + 6H2O + energy
In the formula of photosynthesis, which is 6CO2 + 6H2O -> C6H12O6 + 6O2, there are 6 atoms of carbon. Each molecule of carbon dioxide (CO2) contributes one carbon atom to the formation of glucose (C6H12O6).
There are two atoms of oxygen in an oxygen (O2) molecule.
There are 3 atoms in an oxygen molecule (O2).
The oxide Fe2O3 has 3 oxygen atoms in the molecule.
In the given reaction, the products are 6CO2 and 12H2O. Each CO2 molecule contains one oxygen atom, contributing a total of 6 oxygen atoms, while each H2O molecule contains one oxygen atom, contributing 12 oxygen atoms. Therefore, the total number of oxygen atoms in the products is 6 (from CO2) + 12 (from H2O) = 18 oxygen atoms.
The molecular formula C6H12 contains two different elements: carbon (C) and hydrogen (H). Specifically, there are 6 carbon atoms and 12 hydrogen atoms in this compound.
no. of atoms = no. of moles * avogadros no. no. of atoms = 6 * 6*1023 no. of atoms = 3.6*1024 (ans)
Both formulas are possible molecular formulas for the same empirical formula, CH2.
Glucose and oxygen producing carbon dioxide water and energy C6H12O6 + 6O2 -------> 6CO2 + 6H2O + energy
In the formula of photosynthesis, which is 6CO2 + 6H2O -> C6H12O6 + 6O2, there are 6 atoms of carbon. Each molecule of carbon dioxide (CO2) contributes one carbon atom to the formation of glucose (C6H12O6).
There are two atoms of oxygen in an oxygen (O2) molecule.
There are 2 oxygen atoms in 1 molecule of oxygen.
It depends on how many hydrogens are there and how many oxygen atoms there are.
There are four oxygen atoms in one molecule of H3PO4.
There are 2 oxygen atoms in dioxide
There are 3 atoms in an oxygen molecule (O2).