How many bits are needed to represent the decimal number 200?
log2 200 = ln 200 ÷ ln 2 = 7.6... → need 8 bits. If a signed number is being stored, then 9 bits would be needed as one would be needed to indicate the sign of the number.
8 bits if unsigned, 9 bits if signed
8 (assuming unsigned numbers - i.e., you don't reserve a bit for the sign).
Four bytes represent 32 bits. 32 bits represent 4,294,967,296 possibilities.
17 bits would allow a value up to 131071.
Compression is a reduction in the number of bits needed to represent data.
The answer depends on the precision required for the numbers.
If the 8 bits represent a signed number, the range is usually -128 to +127. This is -27 to 27-1.
6 bits 111110 = 32 + 16 + 8 + 4 + 2 + 0
To consider the difference between straight binary and BCD, the binary numbers need to be split up into 4 binary digits (bits) starting from the units. In 4 bits there are 16 possible values from 0000 to 1111 (0 to 15). In straight binary all of these possible combinations are used, thus: 4 bits can represent the decimal numbers 0-15 8 bits can represent the decimal numbers 0-255 12 bits can represent the decimal numbers… Read More
Count them: 643(10)=1010000011(2)
18 in binary is 10010 Since 18 can't be written in term of 2 to the power x, the number of bits needed is 5. The answer is 5
The highest unsigned integer is 255; The highest signed integer is 127.
To represent 256 colors it is needed 8 bit per pixel. 1 bit mean 2 colors, 2 bits mean 4 colors, 3 bits per pixel can represent 8 colors... 8 bits = 256 colors.
byte has 8 bits all bits at 0 = zero all bits at 1 = 255
5 bits are 5 binary digits. If they represent a decimal number, then that number can be anything from zero to 31, and can have either 1 or 2 digits.
4 bits. 24 = 16, so you have 16 different combinations. 4 bits. 24 = 16, so you have 16 different combinations. 4 bits. 24 = 16, so you have 16 different combinations. 4 bits. 24 = 16, so you have 16 different combinations.
45 in binary is 101101, so you need at least 6 bits to represent 45 characters.
A decimal digit requires 4 bits of memory space to represent all possible values. So N decimal digits will require 4N bits to store in decimal format. On the other hand, if the same N decimal digits were stored as a binary number, they should require log2(10N) bits, that is, about 3.32N bits. So storing the decimal representation uses about 20% more memory. To put it another way, 4 bits is capable of holding one… Read More
41 in decimal is 0100 0001 in BCD (this is 8 bits not 6 bits) 41 in decimal is 101001 in binary (this is 6 bits, but binary not BCD) There is no 6 bit BCD representation of the decimal number 41!
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
When you convert this decimal number to the binary format, we have 111001001 that has 9 digits so 9bits is required to represent it in normal case. To convert decimals to binary visit http://acc6.its.brooklyn.cuny.edu/~gurwitz/core5/nav2tool.html
At least 8 bits are needed to represent the number 231. 231 ÷ 2 = 115 r 1 115 ÷ 2 = 57 r 1 57 ÷ 2 = 28 r 1 28 ÷ 2 = 14 r 0 14 ÷ 2 = 7 r 0 7 ÷ 2 = 3 r 1 3 ÷ 2 = 1 r 1 1 ÷ 2 = 0 r 1 → 231 is 1110 0111 in binary and… Read More
An infinite number.
Most modern digital cameras use 24 bits (8 bits per primary) to represent a color. But more or less can be used, depending on the quality desired. Many early computer graphics cards used only 4 bits to represent a color.
If this is a homework assignment, please consider trying to answer it yourself first, otherwise the value of the reinforcement of the lesson offered by the assignment will be lost on you. The largest decimal number with 25 digits is 9,999,999,999,999,999,999,999,999. The smallest decimal number in the form 2n-1 which is greater than or equal to that is 19,342,813,113,834,066,795,298,815. That corresponds to 284-1. So, the minimum number of binary bits required to represent the decimal… Read More
Just as with the base 10 numbering system, there is no 'largest number' in binary. Whichever number you think of as the largest can always be made larger by the addition of an extra digit on the end. Infinity exists in all bases, but by its nature does not take an integer value. But if you are talking about a specific amount of bits (in a computer) to represent a number, then there is. Example… Read More
255 is the largest decimal number. 1 byte (8 bits) can store 256 *values* (0-255).
If you mean "64 different characters", you need log2(64) = 6 different bits.
A 4 BCD code is a 4 decimal-digit BCD code, thus a 16 digit binary-code. You take the decimal number 3545. It's BCD code is 0011 0101 0100 0101 where every 4 bits represent a decimal digit.
To achieve the answer to what the decimal equivalent of the largest binary number with five places (or bits) is, work this equation: The formula is 2_ -1 where n is the number of bits. That will get you where you need to be.
You can represent 2^12 or 4096 numbers in 12 bits, if that's what you mean?
A 32 binary number is a number stored by a computer in 32 bits. it can represent: 1) An unsigned number in the range 0 to 4,294,967,295 2) A signed number in the range -2,147,483,648 to 2,147,483,647 3) A single precision IEEE floating point number with 1 sign bit, 8 exponent bits and 23 mantissa bits give an accuracy of about 7.2 decimal digits and a range of ± 10^-38 to 10^38
It is somewhat complicated (search for the IEEE floating-point representation for more details), but the basic idea is that you have a few bits for the base, and a few bits for the exponent. The numbers are stored in binary, not in decimal, so the base and the exponent are the numbers "a" and "b" in a x 2b.
How many bits are required in decimal numbers in range 0 to 999 using Straight binary code and BCD code?
10 bits would be required. 10 bits long (10 digits long) can represent up to 1024.
4. 1 bit for 2, 2 bits for 4, 3 bits for 8, 4 bits for 16.
000000 is the lowest number in a 6 bit unsigned binary number (meaning the high order bit is not the sign bit). If it is a signed number then the lowest number would be represented by 100000 which is equivalent to -32 in decimal. Highest unsigned number in 6 bits is decimal 63. Highest signed number in 6 bits is decimal 31.
11 bits. 211 = 2048
If the high-order bit is considered the sign bit then 100000 would represent the largest negative number (in 2's complement - used mostly in computers) which would be equivalent to -32 in decimal
How many bits would be required to represent a) An angle in degrees between 0 and 360. b) The milage on a car odometer assuming six decimal digits. c) The delay in a radar echo in ns assuming a maximu?
How many bits would be required to represent: An angle in degrees between 0 and 360 - at least 9 bits with the following values 180, 90, 45, 22.5, 11.25, 5,625, 2.8125, 1.40625, and 0.703125 The milage on a car odometer assuming six decimal digits - at least 20 bits The delay in a radar echo in ns assuming that you want to measure the distance to the moon - at least 32 bits an… Read More
There are 8 bits in a byte. Bits are a digit in a binary number. Binary is a number system that only has 2 symbols (0 and 1) that can be used to represent a number, as opposed to the usual decimal system that we're used to, which has 10 symbols (0, 1, 2, 3, 4, 5, 6, 7, 8, and 9). In computers, all data is stored as a series of 8-bit binary numbers.
If you want an unsigned integer, you can calculate this as log2(12500), rounded up. You can calculate the log2 function (logarithm to the base 2), in this case, by dividing ln(12500) / ln(2).
Floating point numbers are typically stored as numbers in scientific notation, but in base 2. A certain number of bits represent the mantissa, other bits represent the exponent. - This is a highly simplified explanation; there are several complications in the IEEE floating point format (or other similar formats).
A color images uses 16bits to represent a pixel what is the maximum number of different colors that can be represented?
The number of different colors you can represent with 16 bits is 216, or about 65,000 colors.
In computing terms, BCD means binary-coded decimal. It is a class of a binary encodings of decimal numbers. Each decimal number is resresented by a fixed number of bits.
It is 127 = 2^7 - 1
The largest number is 11111111111111 which is 215 - 1. In decimal, that is 32767.
The number of bits required to represent an integer number depends on the size of the integer, there is no absolute answer. Generally speaking, a binary number made up of some number of bits can be considered to directly represent an integer number according to the rules of binary arithmetic. If you specify the question a little differently you can come up with a question that does have an absolute answer. For example, if you… Read More
In theory, 3 bits are enough to represent up to 8 (23) combinations. In theory, 3 bits are enough to represent up to 8 (23) combinations. In theory, 3 bits are enough to represent up to 8 (23) combinations. In theory, 3 bits are enough to represent up to 8 (23) combinations.
7 bits can show all 128 possible arrangements of 'yes' and 'no'. 6 bits can show only 64 possibilities.