There are 6 lone pairs as 3 lone pairs in either F atom.
two
Four
2
2
it was two.
The Lewis structure for Helium is He with two dots next to each other, above the He symbol. The dots must be drawn next to each other, they represent the two electrons found in the 1s-orbital of the Helium atom.
This is a copy:
The flouride ion (F-) has 8 electrons. I can't really draw it with text, but it has 4 pairs of electrons arranged around it a bit like this... .. :F: '' The top and bottom pairs need to be directly above/below the 'F'
a single bond off of As on the left, right, and bottom. Then a pair of electrons above As. Fill in 2 electrons on each side of every Cl to make it complete.
o=c=s with 2 pairs of unshaired electrons on s and o
The Lewis structure for Helium is He with two dots next to each other, above the He symbol. The dots must be drawn next to each other, they represent the two electrons found in the 1s-orbital of the Helium atom.
This is a copy:
The flouride ion (F-) has 8 electrons. I can't really draw it with text, but it has 4 pairs of electrons arranged around it a bit like this... .. :F: '' The top and bottom pairs need to be directly above/below the 'F'
Lead sulfate (PbSO4) is an ionic compound. It consists of a lead ion (Pb2+) and a sulfate ion (SO42-) bound together in an ionic bond. The structure of the sulfate ion is a sulfur atom surrounded by 4 oxygen atoms.
The correct Lewis Structure for the oxygen atom will be an 'O' with two dots above and below, with one dot on the left and on the right sides.
none of the above. or all of the above for plato!
a single bond off of As on the left, right, and bottom. Then a pair of electrons above As. Fill in 2 electrons on each side of every Cl to make it complete.
o=c=s with 2 pairs of unshaired electrons on s and o
The dot structure for bromine dioxide starts with a Br atom in the center. To the left and right is a singly bonded O atom, each with a pair of dots on the three unbonded sides. The Br atom has a pair of dots on the upper and lower unbonded sides.
the structure is as follows: Na + -:O:H ( I couldn't insert it in this box, but Oxygen (O) has 2 electrons above it and 2 electrons below it to fufil the octet.)
I -> 7e- O(3x) -> 3(6e-) = 18e- Since its an IO3- it has an extra electron Total electrons = 18e- + 7e- +1e- = 26e- I is the Central Atom Each O has a single bond with 6 valance electrons and I and 2 Structure : Trigonal Pyramidal
~ .. .. H:O:Cl: ~ .. .. This is incorrect. Hydrogen my only have two electrons to fill it's outer shell. Where as Oxygen and Chlorine prefer eight electrons. The formating on this program does not allow lewis dot structures to be drawn correctly. However the answer is H:O:Cl with another pair of electrons above and below oxygen and again above and below Cl. (like above except with out the ~'s)