six
Yes if drawn within an octagon from a vertex to each of the other vertices will give you 8 triangles within the octagon
An octagon has 16 diagonals.
8
A segment.
n-3 from each vertex.
No.
If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed
16 diagonals* * * * *5. To all vertices except itself and one each on either side.
it really isn't hard 5
5 triangles are formed.
2
Yes if drawn within an octagon from a vertex to each of the other vertices will give you 8 triangles within the octagon
No, not if it is a randomly-drawn 8-vertex shape. Octagons only have all- obtuse angles if it is a regular octagon, like the shape of a stop sign.
In a regular pentagon, the lines of symmetry are drawn from each vertex to the midpoint of the edge directly opposite the vertex, so there are five in all.
A regular octagon has 8 lines of symmetry. See the Related Link below that includes a diagram of an octagon with the lines of symmetry drawn. A non-symmetrical octagon may have between 0-4 lines of symmetry.
A diagonal of a polygon is a segment drawn from one vertex to another non-adjacent vertex in a polygon. This leaves 32 diagonals that can be drawn from one vertex in a 35 sided polygon.
No, I think 5 diagonals would be the maximum from a particular vertex. Let's label the vertices [A through H].For this example, they go clockwise, starting with A and going around to H, so looking at A: B & H are adjacent and both of the segments AB and AH are actually sides of the octagon, not diagonals. The remaining diagonals, from A are:ACADAEAFAG