The formula for determining the number of diagonals in a shape is n(n-3)/2 where n=vertices, (corners or intersections of geometric shapes). For an eight sided shape we replace n with 8. 8(8-3)/2 8(5)/2 (8x5)/2 40/2=20 An octagon contains 20 diagonals. For a further example we can determine the diagonals in a shape with 5 sides: 5(5-3)/2 5(2)/2 (5x2)/2 10/2=5 A Pentagon contains 5 diagonals.
An octagon has 8 sides and 20 diagonals so the question doesn't make sense
An octahedron is a closed 3-d shape with 8 polygonal faces. There are 257 topologically different convex octahedra. The number of diagonals will depend on the precise shape.
8
It is: 8-2 = 6 triangles
(8*15)-16=104 diagonals in a 16 sided polygon.
Sides: 8 Diagonals : 20
It is an 8 sided octagon
8
An octagon has 8 sides and 20 diagonals so the question doesn't make sense
An octahedron is a closed 3-d shape with 8 polygonal faces. There are 257 topologically different convex octahedra. The number of diagonals will depend on the precise shape.
The Shape That Has 8 Sides Is A Octagon Which Has 8 Equal Sides
8
An octagon has 8 sides and 8 angles.
It is: 8-2 = 6 triangles
A concave Hexagon is that hexagon which has one of its internal angle greater than 180 degrees. It can have 8 diagonals. As compared to regular hexagon (Also convex hexagon) it has one less number of diagonals. This is because one line joining two of its vertices (that are at the end of sides forming >180 angle) fall outside the hexagon.
20 diagonals For any n-sides polygon, the formula for the number of diagonals is (n/2) x (n-3), so for an octagon it is (8/2) x (8-3) = 4 x 5 = 20.
A Square has 4 sides, the shape you want that has twice as many sides as this is called a Octagon. ( Oct = 8 - as in Octopus ).