Math and Arithmetic

How many different outcomes if you roll a die and flip a penny?


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2015-09-01 18:57:50
2015-09-01 18:57:50

If you roll a standard die and flip a penny at the same time, there are 12 possible outcomes. You can find this out quickly by multiplying the number of outcomes of the coin (2) by the number of outcomes of the die (6).

Here they are:

Heads, 1

Heads, 2

Heads, 3

Heads, 4

Heads, 5

Heads, 6

Tails, 1

Tails, 2

Tails, 3

Tails, 4

Tails, 5

Tails, 6

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Related Questions

Penny can land in 2 different ways.Cube can land ion 6 different ways.Quarter can land in 2 different ways.All 3 can land in (2 x 6 x 2) = 24 different ways.

If you disregard the sequence of outcomes, there are 6 possible outcomes: 0H 5T 1H 4T 2H 3T 3H 2T 4H 1T and 5H 0T If not, there are 25 = 32 outcomes: TTTTT, TTTTH, TTTHT etc.

2. There is heads and there is tails.

I am guessing SamJoe, means SAM and JOE not one person, so three people flip a coin, we have two outcomes each times, so 23= 8 possible outcomes. If you had n people, there would be 2n outcomes. For example, if two people flip there are 4 outcomes HH TT HT or TH

There are sixteen different outcomes. To figure this you multiply the number of possible outcomes for each coin, which is 2 for all of them. So you take 2^4 which comes out to 16.

-- 8 possibilities if the coins are different colors. -- Only 4 possibilities if you can't tell the coins apart.

Two possible outcomes for each flip. 2,048 possible histories of 11 flips.

There are many meetings with many different outcomes in Lord of the Flies.

There are 24 = 16 ordered outcomes, that is outcomes in which the order of the results is relevant. If not, there are 5 outcomes (0 heads, 1 head, 2 heads, 3 heads and 4 heads).

If you toss eight coins, there are 256 (28) different outcomes.

If each coin is a different color, then there are 32 possible outcomes. If you can't tell the difference between the coins, and you're just counting the number of heads and tails, then there are 6 possible outcomes: 5 heads 4 heads 3 heads 2 heads 1 heads all tails

If you can identify the outcomes with who flipped each coin: eg Joe and Mary = Heads, Sam = Tails, then 23 = 8. Otherwise, 4.

Each coin has two possible outcomes, either Heads or Tails. Then the number of outcomes when all 4 coins are tossed is, 2 x 2 x 2 x 2 = 16.

There are technically 8 possible outcomes if you are talking about the side of the coin it lands on. Each coin has 2 possible outcomes (landing on heads and landing on tails). To figure out the number of outcomes for all the coins you multiply the outcomes for all of the coins together: 2 X 2 X 2= 8.

There are 2 * 6 or 12 outcomes for flipping a coin and spinning a spinner that has 6 different colored sections.

Almost 12 % It's the same as flip a penny ten times. There are 2^10 = 1024 different outcomes (each penny being either head or tail). The ones we can 'use' are those with 3 heads. Let '1' be head and '0' be tail: 0001010100 is a valid outcome - and 1110000000 as well. So how many way can we arrange three 1's in ten spaces? In 120 ways. 120 ways out of 1024 is the answer. 120/1024=0.1171875 = 11.71875 %

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