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The Lewis dot diagram for SiS2 would show Silicon (Si) at the center with one sulfur (S) atom on each side. Each sulfur atom would have six dots around it to represent its valence electrons, while silicon would have four dots around it.
These would be the elements in group 16. The elements in group 16 have six valence electrons. Those valence electrons are represented in a Lewis diagram by surrounding them with six dots. When drawing a diagram for an element with six valence electrons, there should be two pairs of dots (four total), and two separate dots.
The electron dot formula for SF6 would show 6 pairs of dots around the central Sulfur atom, representing the 6 Fluorine atoms bonded to it. The Sulfur atom will have 12 valence electrons around it in total.
The Lewis dot diagram for CN1 (cyano radical) would show the carbon atom with three outer electrons represented as dots, bonded to the nitrogen atom with one outer electron represented as a dot. The nitrogen atom would also have a lone pair of electrons not involved in bonding.
Sulfur dibromide has a dot structure that begins with the S atom in the center. On the left and right sides are a singly bonded Br atom. On the unbonded sides of each atom is a single pair of dots.
it has 6
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six
The Lewis dot diagram for SiS2 would show Silicon (Si) at the center with one sulfur (S) atom on each side. Each sulfur atom would have six dots around it to represent its valence electrons, while silicon would have four dots around it.
These would be the elements in group 16. The elements in group 16 have six valence electrons. Those valence electrons are represented in a Lewis diagram by surrounding them with six dots. When drawing a diagram for an element with six valence electrons, there should be two pairs of dots (four total), and two separate dots.
there are 6 valence electrons in the outermost energy levei
..:O:.. l ..:O-S-O:" l ":O:" (SO4)2- 32 total electrons: 6 per atom plus 2grrr it wont get the spaces right. its 4 oxygen around a sulfur, all single bonds. each oxygen has 6 extra electrons around it
In the electron dot diagram for a sulfur ion, there would be eight dots represented. This is because sulfur typically forms an ion with a 2- charge, so it needs two more electrons to achieve a full outer shell of eight electrons.
There should be 3 dots in the electron dot diagram of a boron (B) atom, as boron has 3 electrons. Each dot represents one valence electron.
S=C=S the equal sign represents a double bond so if you want the dot and cross put 2 dots and 2 crosses either side of the carbon then 4 dots on each sulphur so each atom has each electrons.