2
The third principal energy level (n=3) has s, p, and d sublevels. In the ground state, the zinc atom has all the s, p, and d sublevels in the n=3 energy level occupied. Therefore, the total number of occupied sublevels in the third principal energy level of a zinc atom in the ground state is 3.
I believe that is Zn (zinc) because it's in the d orbitals... wait it's actually... not possible because the configuration you're asking would look like this.{1s2,2s2,2p6,3s2,3d10}... which is completely wrong... but the first set on the d orbital ending in ten would look like this {1s2,2s2,2p6,3s2,3p6,4s2,3d10}... so if the second one is what you're talking about then it would be Zinc... or it's just Ni Nickel because of the other first 2 electrons in the s orbital.
Valence electron configuration of zinc, abbreviated. [Ar] 4s2 3d10 Zinc's oxidation state is 2, so that 4s2 represents the valance electrons though they are at a lower energy level and the 3d10 gives you the full outer electron configuration.
I think it will be zinc. The electron configuration of zinc is: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10 Add up the electrons. 2+2+6+2+6+2+10 = 30 electrons in all, which is the element zinc. As you can see frorm the above electron configuration, all the electrons for the third energy level are filled: 3s2 is filled; 3p6 is fully filled; 3d10 is fully filled. I really hope this helps and doesn't confuse you... :)
Zinc has 2 valence electrons.
10 electrons
The third principal energy level (n=3) has s, p, and d sublevels. In the ground state, the zinc atom has all the s, p, and d sublevels in the n=3 energy level occupied. Therefore, the total number of occupied sublevels in the third principal energy level of a zinc atom in the ground state is 3.
2
I believe that is Zn (zinc) because it's in the d orbitals... wait it's actually... not possible because the configuration you're asking would look like this.{1s2,2s2,2p6,3s2,3d10}... which is completely wrong... but the first set on the d orbital ending in ten would look like this {1s2,2s2,2p6,3s2,3p6,4s2,3d10}... so if the second one is what you're talking about then it would be Zinc... or it's just Ni Nickel because of the other first 2 electrons in the s orbital.
In a zinc-copper reaction, the energy comes from the transfer of electrons between the zinc and copper. The zinc atoms undergo oxidation, losing electrons, while the copper atoms undergo reduction, gaining those electrons. This transfer of electrons releases energy in the form of heat.
2 electrons. The electron configuration of Zn is 2.8.18.2
Valence electron configuration of zinc, abbreviated. [Ar] 4s2 3d10 Zinc's oxidation state is 2, so that 4s2 represents the valance electrons though they are at a lower energy level and the 3d10 gives you the full outer electron configuration.
In a Bohr model, zinc would have 30 protons and 30 electrons distributed in specific energy levels around the nucleus. The electrons would be arranged in shells or orbits, with the innermost shell containing 2 electrons, the second shell with 8 electrons, and the third shell with 18 electrons.
I think it will be zinc. The electron configuration of zinc is: 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10 Add up the electrons. 2+2+6+2+6+2+10 = 30 electrons in all, which is the element zinc. As you can see frorm the above electron configuration, all the electrons for the third energy level are filled: 3s2 is filled; 3p6 is fully filled; 3d10 is fully filled. I really hope this helps and doesn't confuse you... :)
Zinc has two valence electrons.
Zinc has 30 electrons
Metals have 1, 2, or 3 outer energy level electrons. (except lead and zinc which have 4) nonmetals have 4 or more outer electrons in general.