"Divisible by two" means the number can end with 0,2, or 4.
"Divisible by five" means the number can end with 0 or 5.
Combined that means the ONLY digit the number cannot end with is 3; it can end with any of the other four.
Also, I'm presuming that it's not a "five digit number" if it starts with a 0, so only four of the digits are legal there.
All told, there are 4 x 5 x 5 x 5 x 4 possibilities. That's 2000 different possible numbers.
There are 2000 such numbers.
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.
All numbers that are divisible by 6 are even numbers whose digits add up to 3 or a multiple of 3. Example : 284 is not wholly divisible by 6 as although it is even, its digits total 2 + 8 + 4 = 14 which is not divisible by 3. 282 is divisible by 6 as it is even and its digits total 12 which is divisible by 3.
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
64 if repetition is allowed.24 if repetition is not allowed.
There are 2000 such numbers.
If repetition of digits is allowed, then 56 can.If repetition of digits is not allowed, then only 18 can.
5 ^12
There are 2000 such numbers.
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
-123456787
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
125
290