The amount of water that a 18' x 33' x 4 ft. pool holds is between 5000 and 6000 gallons. It has been reported that a more exact number closer to 6000 gallons.
A pool this size can hold up to about 19,106 US gallons of water (18feet x 33feet x 52inches)
You will also need to give the depth of the pool
17000 gallons
If it is neutral than it has 16 electrons because it is equal to the number of protons. If it is 33 sulfur -2 than it has 18 electrons
1 liter= 1.05668821 quarts 13.2 quarts= 1 liter
33 pints16.5 qts or4.12 gallons
700 * 4.26 lbs = 2,982 pounds
33
17,820 gallons. More pool questions answered at bridgecitypools.com
18 x 33 x 5 = 2970 cubic feet 1 cubic foot = 7.48052 gallons therefore, your pool is 22217.1 gallons
Exactly twenty-six thousand seven hundred thirty gallons.
15070 gallons
Go here: http://www.backyardcitypools.com/swimming-pools/Pool-Volume-Calculate.htm
A 33-foot round pool filled to a depth of 4 feet contains 25,700 gallons of water.
A 12-foot round pool with 33-inches of water contains 2,336.4 gallons of water.
Cannot be answered with only these measurements. You need to specify what shape the pool is. Also, for a rectangular pool, the length, width and depth are needed. For a round pool, the diameter and depth are needed.
28,913 US gallons.
Approx 729 US gallons.
15' x 33' x 4' = 1,980 cubic feet = 14,811.43 gallons (rounded)
The volume of water in a pool is caculated as followed Vol = area X Depth X 7.5 = gallons of water where as area is equal to width x length ( which is 18 x 33 ) so you need height or depth to finish the equations