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How many grams of oxygen form when each quantity of reactant completely reacts. 2 KClO3 (s) plus 2 KCl(s) 3O2 (g)?
LisaLundquistgp5380
The balanced chemical reaction equation says that you get 3 moles of O2.
m O2 = ( n O2 ) ( M O2 )
m O2 = ( 3 mol O2 ) ( 32.00 g O2 / mol O2 = 96 g O2<----------
Answer: 96 g of O2 <------------------------------
Wiki User
∙ 9y ago
For every 2 moles of KClO3 that react, 3 moles of O2 are produced according to the balanced equation. So, the number of moles of O2 formed will be half of the moles of KClO3 that react. From there, you can use the molar mass of O2 (32 g/mol) to calculate the grams of O2 formed.
Wiki User
∙ 8y agoFrom 245,1 g of KClO3 96 g oxygen can be obtained.
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