# How many grams of sucrose are needed to make 755 mL of a 40.0 (wv) sucrose solution?

302 g sucrose are needed.

### What are directions on how to make a 1.0M sucrose solution?

molarity (M) = moles/litre of solution To make a 1.0 M sucrose solution, you need the molar mass of sucrose. C12H22O11 (12x12.0) + (22x1.0) + (11x16.0) = (according to wikipedia 342.30 g/mole) Take the 342.20 grams of sucrose and put it into a graduated cylinder and then fill to the 1.0 L mark with water.

### Would the ratio of solute to solvent in a sucrose solution be the same as in a glucose solution?

No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.

### How do you prepare 0.1N of sucrose solution?

N should be M, meaning number of mole (N) per litre. Concentration equals the number of mole per litre, or simply C=N/V. We know the concentration is 0.1 mol/L One mole of sucrose = 342g (from the molecular formula C12H22O11) so 0.1 mol = 34.2g. To make a 0.1 M sucrose solution, mix 34.2 grams of sucrose into every litre of water.

### How many grams of NaCl are needed to make an NaCl solution?

It depends how strong a solution you want to make. The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre. For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.

### What is the amount of solute in grams needed to make 2.5 percent solution od NaCl in 500ml of water?

### What mass of sucrose C12H22O11 should be combined with 472 g of water to make a solution with an osmotic pressure of 8.95 ATM at 300K?

I finally figured out how to answer this question if you still need the help for it. you use the osmotic pressure equation: TT = (M)(R)(T) R= .08206 L*ATM/mol *k (this is your constant) T= temperature in Kelvin 300K TT=Pressure in ATM 8.95 Now you have to (M) Molarity. 8.95atm/.08206*300= .3635 mols/1L now multiply that in a chain of conversions= 0.3635mols/L*342.12 g/mol(MM of sucrose)*472ml(grams of water since 1g is equal to 1ml)= 58698 and then…