67.5 grams of H2O
The answer is 165,5 g water.
Two moles of water are produced.
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.
If 3 grams of magnesium are used to form 4 grams of magnesium oxide, then 1 gram of oxygen is used in the reaction. This means 1 gram of oxygen remains unused.
The mass fraction oxygen in water is 0.8881.m oxygen = ( 0.8881 ) ( 0.18 g H2O ) = 0.16 g oxygen in 0.18 g of H2O
The answer is 165,5 g water.
Two moles of water are produced.
First find the percentage by mass of oxygen in water. The formula for water is H2O, showing that water contains two hydrogen atoms for every atom of oxygen. The gram atomic masses of hydrogen and oxygen are 1.00794 and 15.9994 respectively. Therefore, the percentage of oxygen in water is 100{15.9994/[15.9994 + 2(1.00794)]} or about 88.8 %, to the justified number of significant digits; the ratio of the maximum mass of water that can be made from a given mass of oxygen is 1/0.888 or about 1.126; and the answer to the question is this number multiplied by the stated mass of oxygen, or 24.9 grams, to the justified number of significant digits.
The atomic mass of hydrogen is 1.008 and the molecular mass of water, with formula H2O, is 18.015. Therefore, the mass of hydrogen to that of water has the ratio of 2(1.008)/18.015 = about 0.1119, and the answer to the problem is 300/0.1119 = 2.68 X 103 grams, to the justified number of significant digits.
There are 424 grams of oxygen in 477 grams of water. 8 times 53 equals 424.
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
7
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
25.78g
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
25