15.37684 joules
15480.80
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
21 grams through 71 degrees is 21x71 calories.
3.50 J
mmmm enthalpy
15480.80
The answer is 53,683 kJ.
It take 4.2 Joules to raise 1 gram of water by 1 degree Celsius. Each gram of water is heated by 1.26 Joules, creating an increase in temperature of .3 degrees Celsius.
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams
21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.
21 grams through 71 degrees is 21x71 calories.
3.50 J
mmmm enthalpy
1935 J (apex)
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
q = mass*specific heat*change in temperature q = (750 g water)(4.180 J/gC)(75.0o C - 25.0o C) = 1.57 X 105 Joules ==============
It takes 4186 joules to raise the temperature of 1 kilogram of water by 1 degree Celsius. The mass does make a difference.