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2520 Joules = (X)(4.180J/gC)(30C-10C)

2520J = 83.6X

30.14 grams of water.

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Wiki User

14y ago
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12y ago

q(Joules) = mass * specific heat * change in temp.

q = (200 grams)(4.180 J/gC)(40.0 C - 10.0 )

= 2.51 X 10^4 Joules

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Wiki User

12y ago

q(Joules) = mass * specific heat * change in temperature.

q = (15 grams)(4.180 J/gC)(40 C - 30 C)

= 627 Joules

-----------------------( call it 630 Joules )

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Wiki User

8y ago

The answer is 1256 joules.

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Wiki User

9y ago

do your hw

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Wiki User

10y ago

150*10*4.18

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Anonymous

Lvl 1
4y ago

5

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Anonymous

Lvl 1
3y ago

42j

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Q: What is the total amount of heat energy in joules absorbed by 25.0 grams of water when the temperature of the water increased from 24.0 C to 36.0 C?
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