The first thing that is required is the amperage of the motor. I = HP x 746/1.73 x E x %eff x pf. This comes to about 277 amps. The second formula to use to find KVA is KVA = I x E x 1.73/1000 = 277 x 480 x 1.73/1000 = 230. The minimum size generator will be 230 KVA.
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480 volts is probably 3-phase (Line to line) voltage, so: 1500K / (480 x 1.732) = I = 1804Amps
kva required for fridge
one
How much KVA generator is required to run two AC of 1.5 tone
Depends on the kva rating of the devices to be tested using a transformer.
What is the minimum height required for chimney of 100 KVA DG Set which is kept in
kva and kw are related as KVA = (KW/PF) pf:power factor
1000 VA = 1 kva
1000 VA = 1 kva
Rating for DG set and any of electrical machines is calculated in KVA. KVA is calculated as KW/pf. One can calculate the required KVA for DG set with this formulation: (KW/pf)/load rate. For example KW=110, pf=0.8 and one loads the DG at 75%, so KVA= (110/0.8)/0.75=185 KVA.
20.44 kva
4kva
There is appoximately zero kVA in 14amp, .5 volt AC.