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There are always ONE mole of gas in 22,4 L gas of any kind (even gaseous mixtures like air) at stp.

So 68.5 (L) / 22.4 (L/mole) = 3.06 mole gas in 68.5 L (at STP)

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8y ago
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13y ago

67.2 (L) / 22.4 (L/mole) = 3.00 mole of ANY gas at STP

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13y ago

3 moles at STP are present. 1 mole of a gas occupies 22.4 liters at STP. So 67.2/22.4 = 3.

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11y ago

One mole of any gas occupies 22.4 liters of space at standard temperature and pressure. Given 7.31 moles, you simply multiply that by 22.4 and get the answer of 163.74 liters.

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10y ago

The answer is 0,305 moles at 1 at and 25 0C.

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Q: How many moles are there in 67.2 liters of carbon dioxide at STP?
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