To calculate the number of moles in 20g of borax (Na2B4O7), we first need to find the molar mass of borax. By adding the atomic masses of all the elements in borax, we get a molar mass of approximately 201.22 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting in the values, we find that there are approximately 0.10 moles of borax in 20g. Since there are four boron atoms in one molecule of borax, the number of moles of B (boron) would be 0.10 moles * 4 = 0.40 moles.
The mole ratio to convert from moles of a to moles of b is determined by the coefficients of a and b in the balanced chemical equation. For example, if the balanced equation is 2A + 3B -> 4C, the mole ratio would be 3 moles of B for every 2 moles of A.
There are 17 elements in a molecule of borax: sodium (Na), boron (B), oxygen (O), and hydrogen (H).
From the balanced reaction, 3 moles of A2 produce 2 moles of D. Therefore, 5 moles of A2 will produce (5/3) x 2 moles of D, which is approximately 3.33 moles of D. Excess B indicates that there is more than enough B to completely react with the 5.00 moles of A2.
Borax has the Formula: Na2B4O7·10H2O or Na2[B4O5(OH)4]·8H2O So the elements are sodium (Na), boron (B), oxygen (O) and hydrogen (H)
Borax has the Formula: Na2B4O7·10H2O or Na2[B4O5(OH)4]·8H2O So the elements are sodium (Na), boron (B), oxygen (O) and hydrogen (H)
The mole ratio to convert from moles of a to moles of b is determined by the coefficients of a and b in the balanced chemical equation. For example, if the balanced equation is 2A + 3B -> 4C, the mole ratio would be 3 moles of B for every 2 moles of A.
There are 17 elements in a molecule of borax: sodium (Na), boron (B), oxygen (O), and hydrogen (H).
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boron
borax
The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / moleTo convert moles to atoms:atoms B = 2.47 mol B6.02 x 1023 atoms B = 1.49E+24 atoms B1 mol BMultiply by atoms per mole. Moles cancel out.
From the balanced reaction, 3 moles of A2 produce 2 moles of D. Therefore, 5 moles of A2 will produce (5/3) x 2 moles of D, which is approximately 3.33 moles of D. Excess B indicates that there is more than enough B to completely react with the 5.00 moles of A2.
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
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20 Mule Team Borax
The atomic weight of B is 10.8 g/mol1. Convert grams of B to moles of B:moles B = 96.3 g B1 mol = 8.91 mol B10.8 gMultiply by moles per gram. Grams cancel out.The atomic weight of S is 32.1 g/mol2. To convert 8.91 moles of S to grams of S:grams S = 8.91 mol S32.1 g = 286 g S1 molMultiply by grams per mole. Moles cancel out.Note that since the atomic weight of S is larger than the atomic weight of B, the mass of the same number of moles is also larger.