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Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoThe answer is 7, moles HCl.
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How many moles of HCl are needed to react with 2.3 moles of Zn in the following reaction?
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
What is the limiting reagent in a reaction?
The limiting reagent in a reaction is the reactant that runs out first. For example, if you are reacting 10 moles of HCl and 5 moles of NaOH, you will get 5 moles of H20, 5 moles of NaCl, and 5 moles of HCl, because the remaining HCl had nothing to react with. Therefore, the NaOH is the limiting reagent.
How many moles of HCl can 0.055 g of calcium carbonate neutralize?
First write the balanced chemical equation for this reaction CaCO3+2HCl-->CaCl2+H2O+CO2 It is clear from this equation that one mol of HCl can react with half a mol of CaCO3. Thus, one half of .025 mols CaCO3 will react with .025 mols HCl. That makes .0125 mols CaCO3.
How many moles are in 67.4 g of HCI?
67,4 g HCl is equivalent to 1,85 moles.
How many moles of hcl are needed to react with 4 moles of cuo?
4 mole cuO X 2/1 = 8 mole Hcl
How many moles of CuO are needed to react with 4 moles of HCL?
4 mole cuO X 2/1 = 8 mole Hcl
How many moles of HCl are needed to react with 2.3 moles of Zn in the following reaction?
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
How many moles of CO2 form when 15.5 mL of 3.00M HCl solution react?
How many moles of CO2 form when 15.5 ml of 3.00m HCl solution react?
Find out the mass of HCL needed to react completely with 0.20 g of ammonia gass?
Use grams to moles to moles to grams: 0.2 g of ammonia gas (NH3) is equivalent to 0.012 moles of NH3 (divide by 17g/mole) One mole of NH3 reacts with one mole of HCl: NH3 + HCl <=> NH4Cl So we need 0.012 moles of HCl to react with 0.012 moles of NH3 0.012 moles HCl * 36.5 g/mole HCl => 0.43 g HCl
What mass of hydrogen chloride is require to react with 100 g of rust?
Taking rust to be Fe2O3, you would have the following reaction:Fe2O3 + 6HCl ==> 2FeCl3 + 3H2O100 g Fe2O3 x 1 mole Fe2O3/159.7 g = 0.626 moles Fe2O3moles HCl needed = 0.626 moles Fe2O3 x 6 moles HCl/mole Fe2O3 = 3.76 moles HCl neededMass HCl needed = 3.76 moles HCl x 36.5 g/mole = 137 g HCl needed
How many grams of HCl are needed to obtain 1.0 liter of a 0.22 M HCl solution?
First.Molarity = moles of solute/Liters of solution0.22 M HCl = X moles/1.0 L= 0.22 moles HCl--------------------------Second.0.22 moles HCl (36.458 grams/1 mole HCl)= 8.0 grams hydrochloric acid needed===========================
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
How many moles of hcl are needed to react with 2.3 moles of zinc the products of the reaction are zinc chloride and hydrogen gas 1 Zn plus 2 HCl -- 1 ZnCl2 plus 1 H2?
The balancing ratio, already in the reaction equation, is 1 to 2, so for 2.3 mol Zn double HCl is needed: 2*2.3 = 4.6 mol HCl
How would you find the answer to this question How many moles of HCl can be formed when moles of hydrogen gas react with chlorine?
For each mole of hydrogen gas (H2) reacting with chlorine gas (Cl2), you will get 2 moles of HCl. H2 + Cl2 = 2 HCl
How many milliliters of 0.248M HCl are needed to react with 1.36 grams of zinc to produce hydrogen?
First, write a balanced equation for this reaction. The reactants are HCl and Zn and the products are ZnCl2(aq), and H2(g). For how to write a balanced equation, see the Related Questions to the left. Then, convert the grams of Zn into moles of Zn. To do that, see the Related Questions to the left. Then use stoichiometry to determine how many moles of HCl are necessary to react with that number of moles of Zn. See the Related Questions to the left for how to solve stoichiometry problems. Finally, determine how many milliliters of solution you need to get that many moles of HCl. To do that, use this equation: number of moles = number of liters * molarity
How many millimeters of a 2 Molar solution of hydrochloric acid are needed to completely react with 75 grams of iron sulfide?
FeS + 2HCl >> FeCl2 + H2S 75 grams FeS (1mole FeS/87.92 grams)(2 mole HCl/1 mole FeS) = 1.71 moles HCl 2 Molar HCl = 1.71 moles HCl/Liters = 0.855 Liters HCl, or as asked for; 855 milliliters of hydrochloric acid needed
