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How many moles of HCl are needed to react with 2.3 moles of Zn in the following reaction?
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
How many grams of hydrochloric acid are needed to react completely with 4.6 g of calcium?
To determine the grams of hydrochloric acid (HCl) needed to react completely with 4.6 g of calcium (Ca), we first need to use the balanced chemical equation for the reaction: [ \text{Ca} + 2\text{HCl} \rightarrow \text{CaCl}_2 + \text{H}_2 ] From the equation, one mole of calcium reacts with two moles of hydrochloric acid. The molar mass of calcium is approximately 40.08 g/mol, so 4.6 g of calcium corresponds to about 0.115 moles of Ca. This means it would require about 0.230 moles of HCl. The molar mass of HCl is approximately 36.46 g/mol, so you would need about 8.38 g of HCl to react with 4.6 g of calcium.
How many moles are in 67.4 g of HCI?
67,4 g HCl is equivalent to 1,85 moles.
How many grams are 0.7 moles of HCL?
The answer is 25,522 g.
How many moles of hcl are needed to react with 4 moles of cuo?
4 mole cuO X 2/1 = 8 mole Hcl
How many moles of HCl are needed to react with 2.3 moles of Zn in the following reaction?
I assume you mean this reaction. Zn + 2HCl --> ZnCl2 + H2 2.3 moles zinc (2 moles HCl/1 mole Zn) = 4.6 moles hydrochloric acid needed ========================
How many moles of CuO are needed to react with 4 moles of HCL?
The balanced chemical equation for the reaction between CuO and HCl is: CuO + 2HCl --> CuCl2 + H2O This equation shows that 1 mole of CuO reacts with 2 moles of HCl. Therefore, to react with 4 moles of HCl, you would need 2 moles of CuO.
How many moles of NaOH will it take to neutralize 0.61 L of 0.46 M HCl?
1st Get the balanced equation NaOH + HCl -> NaCl + H2O Find the number of moles in HCl; n = cv n = 0.46x0.61 n = 0.2806 moles the number of moles of HCl and NaOH is the same so 0.2806moles will be needed
How many milliliters of a 3.00 M solution of hydrochloric acid are needed to completely react with 25.0 g of zinc sulfide according to the chemical reaction?
To determine the volume of 3.00 M HCl needed to react with 25.0 g of zinc sulfide (ZnS), you first need to balance the chemical equation and calculate the moles of ZnS. Utilize the mole ratio to find the moles of HCl needed, then use the molarity of HCl to convert moles to volume (in mL).
What is the molarity of a HCl solution if 2.50 L is needed to react with 12.7 g of Al?
To find the molarity, first calculate the moles of HCl by using the molar mass of Al to convert grams of Al to moles, since HCl and Al react in a 1:1 ratio. Then, divide the moles of HCl by the volume in liters to get the molarity. Molarity = moles of solute / volume of solution in liters.
Find out the mass of HCL needed to react completely with 0.20 g of ammonia gass?
Use grams to moles to moles to grams: 0.2 g of ammonia gas (NH3) is equivalent to 0.012 moles of NH3 (divide by 17g/mole) One mole of NH3 reacts with one mole of HCl: NH3 + HCl <=> NH4Cl So we need 0.012 moles of HCl to react with 0.012 moles of NH3 0.012 moles HCl * 36.5 g/mole HCl => 0.43 g HCl
How many mL of 0.1010 M HCl will be needed to titrate 0.3151 grams of primary standard Na2CO3?
To determine the volume of HCl needed, first calculate the moles of Na2CO3 using its molar mass. Then use the balanced chemical equation to find the moles of HCl required to fully react with the moles of Na2CO3. Finally, use the concentration of the HCl solution to calculate the volume required using the formula: moles = molarity x volume (in liters).
How many moles of NaCl are formed from the reaction between 1.4 moles of HCl and 2.8 moles NaOH?
The balanced chemical equation for the reaction between HCl and NaOH is: HCl + NaOH -> NaCl + H2O Since the stoichiometry of the reaction is 1:1 for NaCl and HCl, if 1.4 moles of HCl react, then 1.4 moles of NaCl will be formed.
How many grams of sodium carbonate is needed to react with 18.1 ml of 0.23M HCL?
Balanced equation always first!! Na2CO3 + 2HCl -> 2NaCl + CO2 + H2O Find moles HCl by---Molarity = moles of solute/Liters of solution (18.1 ml = 0.0181 L) 0.23 M HCl = moles HCl/0.0181 liters = 0.004163 moles HCl Drive back against sodium carbonate stoichometrically 0.004163 moles HCl (1 mole Na2CO3/2 mole HCl)(105.99 grams/1 mole Na2CO3) = 0.22 grams Na2CO3 needed --------------------------------------------
How many moles of hcl are needed to react with 2.3 moles of zinc the products of the reaction are zinc chloride and hydrogen gas 1 Zn plus 2 HCl -- 1 ZnCl2 plus 1 H2?
According to the balanced chemical equation, the stoichiometry of the reaction is 1 mole of zinc reacts with 2 moles of hydrochloric acid. Therefore, to react with 2.3 moles of zinc, you would need 4.6 moles of hydrochloric acid (2.3 moles zinc * 2 moles HCl / 1 mole Zn).
How many moles of hcl are needed to react with 0.35 g of NAHCO3?
The answer to the conversion is that 35.0 grams of hydrochloride (HCL) equals 0.76 moles. The conversion rate is 35.0 grams divided by 46 gram per mole. A mole is the molecular weight of a substance.
