2HCl + Ca(OH)2 --> CaCl2 + 2H2O That means you need twice as many moles of HCl as you have of the Ca(OH)2 I'll let you do the math.
Depends on the chemical formula, which tells you the molar ratios with the coefficients in front of the compounds.
Balanced equation.
2HNO3 + Ca(OH)2 -> Ca(NO3)2 + 2H2O
1 mole Ca(OH)2 (2 mole HNO3/1 mole Ca(OH)2)
= 2 moles nitric acid should do it.
Balanced equation first.
CaCO3 + 2HCl -> CaCl2 + CO2 + H2O
2.5 moles CaCO3 (2 mole HCl/1 mole CaCO3)
= 5.0 moles HCl required
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2 moles of calcium hydroxide are necessary.
Ca(OH)2 + 2HCl ==> 2H2O + CaCl2
H20+CaCl2
20 moles of NaOH needed to neutralize 20 moles of nitric acid
3 moles KOH to neutralize 3 moles HNO3 : 3 mol OH- will react with 3 mol H+
97.8 - 98.2 98 worked for me
The answer is 0,07 moles Ca(OH)2.
Any base will neutralize an acid. Most commonly used is baking soda. Be careful to not add too much too quickly. If possible find out what concentration the sulfuric acid is. The reaction of the base being added to the acid can create large amounts of heat. This heat could melt plumbing pipes, floor drains, battery compartments, etc. It is best to dilute the baking soda (base) with water before adding it to the acid. I would start with a very diluted solution of water and baking soda and slowly move towards a more concentrated.
6 tablespoons.
20 moles of NaOH needed to neutralize 20 moles of nitric acid
0.0532
0.0932 L
98g
How many grams of KHP are needed to exactly neutralize 36.7 mL of a 0.328 M barium hydroxidesolution
262 - 266
Calcium Carbide is used in "Carbide Lamps". Water, added dropwise to Calcium Carbide yields acetylene plus calcium hydroxide. Acetylene is extremely flammable, giving a colorless flame. The calcium hydroxide present gives the flame its visibility. Calcium Carbide is used in "Carbide Lamps". Water, added dropwise to Calcium Carbide yields acetylene plus calcium hydroxide. Acetylene is extremely flammable, giving a colorless flame. The calcium hydroxide present gives the flame its visibility.
262 - 266
1 mole sulfuric acid for 1 mole calcium chloride
3 moles KOH to neutralize 3 moles HNO3 : 3 mol OH- will react with 3 mol H+
97.8 - 98.2 98 worked for me