How many moles of N 2 reacted if 0.50 mol of NH 3 is produced?

Answer 1

First make the reaction equation balanced for N-atoms (co-existant in both formula)

N2O5 + H2O --> 2 HNO3

So 1.02 mole HNO3 is produced from:

1.02 x 1 (N per HNO3) / 2 (N per N2O5) = 0.51 mol N2O5

Answer 2

Lets assume the reaction:

N2 + H2 -> NH3

Now to balance it:

1 N2 + 3 H2 -> 2 NH3

There is a 2/1 ratio for moles of NH3/N2

So 2 mol NH3 produced for every 1 mol of N2 reacted.

0.50 mol NH3 produced * (1 mol of N2 reacted / 2 mol NH3 produced) =

0.25 mol of N2 reacted.

Answer 3

Need balanced equation here.

N2 + 3H2 -> 2NH3

1.5 moles H2 (2 moles NH3/3 moles H2)

= 1.0 moles ammonia produced

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Answer 4

0.5 [mol Ni(NO3)2] * 2 [mol N per mol Ni(NO3)2] = 1.0 mol N = 0.5 mol N2

Answer 5

There is one mole of N2 per mole of Ni(NO3)2; therefore there is one half mole of N2 in one half mole of Ni(NO3)2.

0.5 mole N2 <--------[ Answer ]

Answer 6

0,325 moles of nitrogen are involved in the reaction.

Answer 7

o.5

Answer 8

50 moles...

Answer 9

Hv