[ 217(g) / 44.013(g/mol) ] * 2(molN/molN2O) = 9.86 mol N
Divide mass (g) by molar mass (g/mol) to get moles of N2O, this should be multiplied by 2 for the stoechiometric factor of atoms N per molecule N2O.
0.251(g N2O) / 44.013(g/mol N2O) ] * 2(mol'N'/mol N2O) =
= [0.00570(mol N2O)] * 2(mol'N'/mol N2O) =
= 0.0114 mol 'N' or 0.00570 mol N2
n(N2O)=0.231/44=0.00525 mol N2O
n(N)=0.00525 * 2=0.002625mol N
Because nitrogen has a diatomic molecule the answer is 0,0055 moles.
Molecular mass of N2O is44gmol-1. there are 0.0114 n moles.
0,225 g of N2O contain 0,005 moles of nitrogen (N2).
molar mass N2O = 44 g/mole 0.215 g x 1 mole/44 g x 2 moles N/mole N2O = 0.00977 moles of N
The number of nitrogen moles is 0,01.
O,01 moles
0,189 g of N2O equal 0,0043 mol.
The answer is 1,52 moles.
When using the preferred resonance structure [ N (triple bond) N (single bond) O ] the bond order of N-O in N2O is 1.
1 mole N = 14.0067g N 78.56g N x 1mol N/14.0067g N = 5.609 moles N
- .. SP linear geometry :N=N-o: ..
There are 0.003659 N2O moles. So there are o.007318 moles of N.
The number of moles is 3,316 (for atomic nitrogen).
0,189 g of N2O equal 0,0043 mol.
The answer is 1,52 moles.
Molar mass: 44.013 g/mole 81.0/44.013=1.84 mole N2O Moles of N 1 mole N2O contains 2 atoms N 1.84 mole N2O contain 1.84*2=3.68 mole N atoms
One molecule of N2O N 2 O contains one atom of oxygen.
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
For this you need the atomic (molecular) mass of NaNO3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaNO3=85.0 grams60.1 grams NaNO3 / (85.0 grams) = .707 moles NaNO3
When using the preferred resonance structure [ N (triple bond) N (single bond) O ] the bond order of N-O in N2O is 1.
The answer is 0,0043 moles of N2.
1 mole N = 14.0067g N 78.56g N x 1mol N/14.0067g N = 5.609 moles N
This is a thermal decomposition reaction.